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Vinvika [58]
3 years ago
11

What physical property helps identify a substance?

Chemistry
2 answers:
Zinaida [17]3 years ago
8 0
The answer is b because density defines that you can see and feel the object.
Digiron [165]3 years ago
5 0
I believe the answer is B. Density, correct me if i'm wrong :)
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lorasvet [3.4K]

Answer:

It is D

Explanation:

Im 90% percent sure

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A chemistry student needs 50.0 g of dimethyl sulfoxide for an experiment. By consulting the CRC handbook of chemistry and physic
Ugo [173]

Answer:

45.45 ml of dimethyl sulfoxide

Explanation:

density of dimethyl sulfoxide is 1.10 g/10⁻³L which is 1.10 g/mL

now we devise the next reasoning:

If           1.10 g of dimethyl sulfoxide have a volume of 1 mL

Then     50 g of dimethyl sulfoxide have a volume of X mL

X = (50 × 1) / 1.10 = 45.45 ml of dimethyl sulfoxide

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3 Points
svp [43]

Answer:

C. Splitting the atom

Explanation:

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A student has a mixture of solid sand and nacl(aq)in a flask to obtain solid nacl from this mixture the student should
maria [59]
In order to obtain solid NaCl, the student should do a few steps.

First, he/she should do filtration. Pass the mixture through a filter paper, where all the sand should be filtered out already because they're not dissolved in the solution plus they're too small to pass through the filter paper.

Next, the filtrate should be left with NaCl (aqueous state). To seperate NaCl with the liquid, the student can either do evaporation or crystallization, depending on how pure or fast he/she wants the results to be. Evaporation involves heating the beaker or whatever apparatus under the bunsen burner until all the liquid has evaporated. Then, some white powder should be left, they're NaCl solid. For crystallization, the student should just put the beaker on a room condition environment, and wait. They might have to wait a month or so for the liquid to completely evaporate itself and left with clear and pure NaCl crystals.
5 0
3 years ago
On the addition of HI
victus00 [196]

Answer:

CH_3-CH(I)-CH(CH_3)-CH_3

I-CH_2-CH_2-CH(CH_3)-CH_3

Explanation:

Given the compound CH_2=CH-CH(CH_3)-CH_3

The steps of reaction:

HI \longrightarrow H^+ + I^-

CH_2=CH-CH(CH_3)-CH_3 + H^+ \longrightarrow CH_3-CH^+-CH(CH_3)-CH_3

<u>But this intermediate product has a resonance: </u>

CH_3-CH^+-CH(CH_3)-CH_3 \longleftrightarrow C^+H_2-CH2-CH(CH_3)-CH_3

The reaction with I-

CH_3-CH^+-CH(CH_3)-CH_3 + I^- \longrightarrow CH_3-CH(I)-CH(CH_3)-CH_3

C^+H_2-CH2-CH(CH_3)-CH_3 + I^- \longrightarrow I-CH_2-CH_2-CH(CH_3)-CH_3

8 0
3 years ago
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