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Novay_Z [31]
3 years ago
5

How many questions are on cumulative tests? on edgenutiy

Physics
1 answer:
Evgesh-ka [11]3 years ago
8 0
Roughly 50 for me i dont know about anyone else
You might be interested in
A converging lens of focal length 20 cm is placed in contact with a diverging lens of focal length 30 cm. The focal length of th
kramer

Answer:

The focal lenth (F) =+10.0cm

Explanation:

The formular for combined focal length (F) is given as;

1/f = 1/f_{1} + 1/f_{2}

In this  question,

F1 = 20cm

F2  = -30cm

Plugging the values into the formuar above,

1/f = 1/20 + 1/(-30)

1/f = 0.05 - 0.033[tex]1/f = -0.017f = [tex]1/ -0.017

f = 58.82cm

i.e. the combination behaves as a converging lens (because of the postive sign) of focal length 58.82cm .

7 0
3 years ago
Can work done=mass*acceleration*displacement(work=m*a*s)
Airida [17]

no, work is = force * distance or displacement


5 0
3 years ago
A wave of wavelength 0.3 m travels 900 m in 3.0 s. Calculate its frequency.
zzz [600]

Answer:

1000 Hz

Explanation:

<em>The frequency would be 1000 Hz.</em>

The frequency, wavelength, and speed of a wave are related by the equation:

<em>v = fλ ..................(1)</em>

where v = speed of the wave, f = frequency of the wave, and λ = wavelength of the wave.

Making f the subject of the formula:

<em>f = v/λ.........................(2)</em>

Also, speed (v) = distance/time.

From the question, distance = 900 m, time = 3.0 s

Hence, v = 900/3.0 = 300 m/s

Substitute v = 300 and λ = 0.3  into equation (2):

f = 300/0.3 = 1000 Hz

6 0
3 years ago
what happens to the volume when temperature is held constant and the pressure is increased to 125 kPa
Semenov [28]
The volume decreases, by a factor of

(the original pressure/(125 kPa).
5 0
3 years ago
A 477 g portion of soup is heated in a microwave oven from 25°C to 90°C, using radiation with a wavelength of 1.55 × 10⁻² m. Ass
zheka24 [161]

To solve this problem we will use the heat transfer equations, to determine the amount of heat added to the body. Subsequently, through the energy ratio given by Plank, we will calculate the energy of each of the photons. The relationship between total energy and unit energy will allow us to determine the number of photons

The mass of water in the soup is 477g

The change in temperate is

\Delta T = (90+273K)-(25+273K) = 65K

Use the following equation to calculate the heat required to raise the temperature:

q = mc\Delta T

Here,

m = Mass

c = Specific Heat

q = (477)(4.184)(65)

q = 129724.92J

The wavelength of the ration used for heating is 1.55*10^{-2}m

The number of photons required is the rate between the total energy and the energy of each proton, then

\text{Number of photons} = \frac{\text{Total Energy}}{\text{Energy of one Photon}}

This energy of the photon is given by the Planck's equation which say:

E = \frac{hc}{\lambda}

Here,

h = Plank's Constant

c = Velocity of light

\lambda = Wavelength

Replacing,

E = \frac{(6.626*10^{-34})(3*10^8)}{1.55*10^{-2}}

E = 1.28*10^{-23}J

Now replacing we have,

\text{Number of photons} = \frac{82240.7}{1.28*10^{-23}}

\text{Number of photons} = 6.41*10^{27}

Therefore the number of photons required for heating is 6.41*10^{27}

4 0
3 years ago
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