Complete Question
A parallel plate capacitor creates a uniform electric field of 5 x 10^4 N/C and its plates are separated by 2 x 10^{-3}'m. A proton is placed at rest next to the positive plate and then released and moves toward the negative plate. When the proton arrives at the negative plate, what is its speed?
Answer:
Explanation:
From the question we are told that:
Electric field 
Distance 
At negative plate
Generally the equation for Velocity is mathematically given by
Therefore
We can rearrange the mirror equation before plugging our values in.
1/p = 1/f - 1/q.
1/p = 1/10cm - 1/40cm
1/p = 4/40cm - 1/40cm = 3/40cm
40cm=3p <-- cross multiplication
13.33cm = p
Now that we have the value of p, we can plug it into the magnification equation.
M=-16/13.33=1.2
1.2=h'/8cm
9.6=h'
So the height of the image produced by the mirror is 9.6cm.
Answer: D. Hydroelectric power
Explanation: Hydroelectric means water power (not exactly but "hydro" is water and electric is well self explanatory)
Answer:
49.63 degree
Explanation:
thickness of glass slab, t = 0.6 cm
angle of incidence = 59 degree
Let r be the angle of refraction
The refractive index of glass, ng = 3/2
refractive index of water, nw = 4/3
refarctive index of glass with respect to water = ng / nw = 3 /2 ÷ 4 /3 = 9 / 8
So, by use of Snell's law
Refractive index of glass with respect to water = Sin i / Sin r
9 / 8 = Sin 59 / Sin r
9 / 8 = 0.857 / Sin r
Sin r = 0.7619
r = 49.63 degree
<u>Weight = (mass) x (acceleration of gravity)</u>
Divide each side by (mass),and we have
Acceleration of gravity = (weight) / (mass)
Acceleration of gravity = 2,970/90 = 33 newtons per kilogram = <em>33 m/s²</em>
