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serg [7]
3 years ago
13

Find the unbalanced force required to accelerate a 6kg mass at 3ms

Physics
1 answer:
Mila [183]3 years ago
5 0

Force (F)=Mass (m)×Acceleration (a).

∴F=ma.

∴F=(2kg)×(3ms2).

∴F=6kgms2=6 Newton. =6N.


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Two 2.0kg bodies A and B collide The velocities before the collision are U1=15i+30j and U2=-10j+5.0j After the collision V1=-5.0
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Use the law of conservation of momentum. Since the momentum is a linear measure, we can treat each of the dimension separately:

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m_1u_{1j}+m_2u_{2j}=m_1v_{1j}+m_2v_{2j}\\v_{2j} = \frac{m_1u_{1j}+m_2u_{2j}-m_1v_{1j}}{m_2}=\frac{(2\cdot 30+2\cdot5-2\cdot20)kg\frac{m}{s}}{2kg}=15\frac{m}{s}

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\Delta E_k = E_{ku}-E_{kv} = \frac{1}{2}m(u_1^2+u_2^2-v_1^2-v_2^2)=\\=\frac{1}{2}2kg(1125+125-425-325)\frac{m^2}{s^2}=500J

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