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3 years ago

Find the unbalanced force required to accelerate a 6kg mass at 3ms

Physics

1 answer:

Mila [183]3 years ago

5 0

Force (F)=Mass (m)×Acceleration (a).

∴F=ma.

∴F=(2kg)×(3ms2).

∴F=6kgms2=6 Newton. =6N.

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A light beam which is amplified into a strong concetrated beam of light is known as A) a laser. B) a transistor. C) a microwave

murzikaleks [220]

The correct answer is A. a <em>Laser</em>.

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3 years ago

Read 2 more answers

19.A 20 kg sign is pulled by a horizontal force such that the single rope (originally vertical) holding the sign makes an angle

Andreyy89

Answer:

A) $T=209.94N$

B) $F=75.24N$

Explanation:

Using the free body diagram and according to Newton's first law, we have:

$\sum F_y=Tcos(21^\circ)-mg=0(1)\\\sum F_x=F-Tsin(21^\circ)=0(2)$

A) Solving (1) for T:

$T=\frac{mg}{cos(21^\circ)}\\T=\frac{20kg(9.8\frac{m}{s^2})}{cos(21^\circ)}\\T=209.94N$

B) Solving (2) for F:

$F=Tsin(21^\circ)\\F=(209.94N)sin(21^\circ)\\F=75.24N$

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3 years ago

Why is pure oxygen stored as a liquid under pressure

yKpoI14uk [10]

<h2>Answer: It is highly flammable.</h2>

Explanation:

Liquid oxygen is created from oxygen atoms that have been forced to assume the liquid state due to <u>compression (change of pressure) and temperature modification. </u>

Specifically this is achieved by cooling the oxygen enough to change it to its liquid state. So,<u> as the temperature drops, the atoms move more slowly because they have less energy. </u>

In this sense, in the liquid state it is easier to store and mobilize oxygen, taking into account that it is a highly flammable gas.

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3 years ago

84. Three resitors each of value 30 respectively are connected in a parallel

kati45 [8]

Answer:

each resistor draws 1/3 of an amp or 0.33333 amps

Explanation:

V = I * R

V = 10 volts

R = 30 ohms

10 = I * 30 Divide by 30

10/30 = I

I = 0.33333

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2 years ago

If it requires 8.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

jenyasd209 [6]

Answer:

The amount of work done required to stretch spring by additional 4 cm is 64 J.

Explanation:

The energy used for stretching spring is given by the relation :

$E = \frac{1}{2}kx^{2}$ .......(1)

Here k is spring constant and x is the displacement of spring from its equilibrium position.

For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

$8 = \frac{1}{2}\timesk\times k \times(0.02)^{2}$

k = 4 x 10⁴ N/m

Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).

Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

$E = \frac{1}{2}\times4\times10^{4}\times (0.06)^{2}$

E = 72 J

But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :

E = ( 72 - 8 ) J = 64 J

7 0

3 years ago