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3 years ago

At its closest point, Mercury is approximately 46 million kilometers from the sun. What is this distance in AU?

1 answer:

7 0

This problem can be solved using the following relation: 1 kilometer = 6.6846e-9 AU. Since we are already given the number of kilometers, we simply have to multiply it to its equivalent in AU to solve for the equivalent distance. This is done below:

46 000 000 * <span>6.6846e-9 = 0.3 AU</span>

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Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the mass of Object 1 is one-fourth the original

Black_prince [1.1K]

Answer:

New gravitational force, F' = 216 units

Explanation:

Given that,

Gravitational force between object 1 and 2, F = 72 N

The gravitational force between two objects is given by :

$F=\dfrac{Gm_1m_2}{r^2}$

$\dfrac{Gm_1m_2}{r^2}=72$ ............(1)

If the mass of object 1, $m_1'=\dfrac{m_1}{4}$

$m_2'=3m_2$

If the distance between objects is halved, $r'=\dfrac{r}{2}$

Let new gravitational force is F'. It is changed to :

$F=\dfrac{Gm'_1m'_2}{r'^2}$

$F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}$

$F'=3\times \dfrac{Gm_1m_2}{r^2}$

$F'=3\times F$

$F'=3\times 72$

F' = 216 units

So, the new gravitational force will be 216 units.

6 0

3 years ago

Why does the value of g vary from place to place?

NemiM [27]

Answer:

The variation in apparent gravitational acceleration (g) at different locations on Earth is caused by two things (as you implied). ... The distance between the centers of mass of two objects affects the gravitational force between them, so the force of gravity on an object is smaller at the equator compared to the poles.

8 0

3 years ago

Consider two diffraction gratings. One grating has 3000 lines per cm, and the other one has 6000 lines per cm. Both gratings are

Usimov [2.4K]

Answer:

<em>The 6000 lines per cm grating, will produces the greater dispersion .</em>

Explanation:

A diffraction grating is an optical component with a periodic (usually one that has ridges or rulings on their surface rather than dark lines) structure that splits and diffracts light into several beams travelling in different directions.

The directions of the light beam produced from a diffraction grating depend on the spacing of the grating, and also on the wavelength of the light.

For a plane diffraction grating, the angular positions of principle maxima is given by

(a + b) sin ∅n = nλ

where

a+b is the distance between two consecutive slits

n is the order of principal maxima

λ is the wavelength of the light

From the equation, we can see that without sin ∅ exceeding 1, increasing the number of lines per cm will lead to a decrease between the spacing between consecutive slits.

In this case, light of the same wavelength is used. If λ and n is held constant, then we'll see that reducing the distance between two consecutive slits (a + b) will lead to an increase in the angle of dispersion sin ∅. So long as the limit of sin ∅ not greater that one is maintained.

7 0

3 years ago

Harry Potter is chasing his nemesis Draco Malfoy during a quidditch match. Initially, Harry is 35m behind Draco, who has just sp

Sophie [7]

Answer:

the acceleration of harry is equal to 66.126 m/s²

Explanation:

given,

harry is 35 m behind Draco

speed of Draco = 40 m/s

original speed of harry = 50 m/s

acceleration = ?

time taken by the Draco

t = $\dfrac{r}{u} =\dfrac{75}{40}$

t = 1.875 s

distance covered by Harry

d = 35 + 175 = 210 m

to calculate the acceleration of harry

$s = u t+ \dfrac{1}{2}at^2$

$210 = 50\times 1.875+ \dfrac{1}{2}\times a\times 1.875^2$

a × 3.516 × 0.5 = 116.25

a = 66.126 m/s²

hence, the acceleration of harry is equal to 66.126 m/s²

3 0

4 years ago

What is the smallest possible piece an element in broken down into my normal laboratory processes

lozanna [386]

answer would be: A. atom

8 0

3 years ago