Since this traffic flow has a jam density of 122 veh/km, the maximum flow is equal to 3,599 veh/hr.
<u>Given the following data:</u>
- Jam density = 122 veh/km.
<h3>How to calculate the
maximum flow.</h3>
According to Greenshield Model, maximum flow is given by this formula:

<u>Where:</u>
is the free flow speed.
is the Jam density.
In order to calculate the free flow speed, we would use this formula:

Substituting the parameters into the model, we have:

Max flow = 3,599 veh/hr.
Read more on traffic flow here: brainly.com/question/15236911
Answer:
6.9
Explanation:
I had the same question lol your welcomr if itd not right in sorry
9514 1404 393
Answer:
13/80
Explanation:
The product is ...
(1 3/10)×(1/8) = (13/10)×(1/8) = (13×1)/(10×8) = 13/80
Answer:

Explanation:
Given

Required
Convert to standard form

From laws of indices

So,
is equivalent to





Hence, the standard form of
is 
Answer:

Explanation:
From the information given:
Life requirement = 40 kh = 40 
Speed (N) = 520 rev/min
Reliability goal
= 0.9
Radial load
= 2600 lbf
To find C10 value by using the formula:

where;


The Weibull parameters include:



∴
Using the above formula:


![C_{10} = 3640 \times \bigg[\dfrac{1248}{0.9933481582}\bigg]^{\dfrac{3}{10}}](https://tex.z-dn.net/?f=C_%7B10%7D%20%3D%203640%20%5Ctimes%20%5Cbigg%5B%5Cdfrac%7B1248%7D%7B0.9933481582%7D%5Cbigg%5D%5E%7B%5Cdfrac%7B3%7D%7B10%7D%7D)

Recall that:
1 kN = 225 lbf
∴

