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3 years ago

HELP PLS !!!! :))Formula unit of Sr and CI Formula unit of AI and S

Chemistry

1 answer:

xenn [34]3 years ago

4 0

Answer : The formula unit of Sr & Cl is $SrCl_2$ and the formula unit of Al & S is $Al_2S_3$

Explanation :

Formula unit : it is defined as the lowest number ratio of ions of an elements in an ionic compound or covalent compound.

For the formula unit of Sr & Cl, two chloride ions $(Cl^-)$ are needed to neutralize the one strontium ion $(Sr^{2+})$ .

For the formula unit of Al & S, three sulfide ions $(S^{2-})$ are needed to neutralize the two aluminium ion $(Al^{3+})$ .

The formula unit of $SrCl_2$ and $Al_2S_3$ are shown below.

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t the R group in the reagent over the arrow be isopropyl. (i.e. The reagent is LiN[CH(CH3)2]2.) Now, fill in the blanks. This re

Tanzania [10]

Answer:c. Hofmann's; less

Explanation:

The Hofmann elimination process, named after its discoverer, the German chemist August Wilhelm Von Hofmann rule states that the major alkene product is the least substituted and least stable product when it comes to asymmetrical amines. The Hofmann elimination can be illustrated in t e formation of “Hoffman” products in elimination reactions using a less common, LDA LiN[CH(CH3)2]2 Lithium Di-isopropyl Amide (LDA) usually with base potassium t-butoxide which will give rise to a less substituted alkene.

This reaction will follow Hofmann's_____ rule and will form the ___less______ substituted alkene.

3 0

3 years ago

Read 2 more answers

A block of aluminum occupies a volume of 0.015 L and has a mass of 40.5 g. What is its density

yan [13]

Answer:

<h2>Density = 2700 g/L</h2>

Explanation:

Density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

From the question

volume = 0.015 L

mass = 40.5 g

Substitute the values into the above formula and solve for the Density

That's

$Density = \frac{40.5}{0.015}$

We have the final answer as

Density = 2700 g/L

Hope this helps you

7 0

2 years ago

In which aqueous solution will the most ZnS dissolve?

sineoko [7]

1) 0.1 M NaCl
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8 0

3 years ago

Read 2 more answers

The limiting reactant, O2, can form up to 2.7 mol Al2O3. What mass of Al2O3 forms?

Margaret [11]

Answer:

280 g Al₂O₃

Explanation:

To find the mass, you need to multiply the given value by the molar mass. This will cause the conversion because the molar mass exists as a ratio; technically, the ratio states that there are 101.96 grams per every 1 mole Al₂O₃. It is important to arrange the ratio in a way that allows for the cancellation of units. In this case, the desired unit (grams) should be in the numerator. The final answer should have 2 sig figs to reflect the given value (2.7 mol).

Molar Mass (Al₂O₃): 101.96 g/mol

2.7 moles Al₂O₃ 101.96 g
------------------------ x ------------------- = 275 g Al₂O₃ = 280 g Al₂O₃
1 mole

5 0

1 year ago

Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom

ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

Average atomic weight of Hafnium= sum of all the atomic weights of the isotopes/ Total occuring isotopes

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

6 0

2 years ago