0.0821 L-atm/mol-K
8.314 kPa-L/mol-K
Answer:
V₂ = 4.34 L
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 3.50 L
Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)
Initial temperature = 330 K
Final temperature = 273 K
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.5 atm × 3.50 L × 273 K / 330 K × 1 atm
V₂ = 1433.3 atm .L. K / 330 k.atm
V₂ = 4.34 L
Given :
Number of He atoms, 
atoms.
To Find :
How many grams are their in given number of He atoms.
Solution :
We know, molecular mass of He is 4 g. It means that their are 
atoms in 4 g of He.
Let, number of gram He in 
atoms is x , so :
Therefore, grams of He atoms is 22.58 g .
Answer:
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Explanation:
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