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stellarik [79]
3 years ago
15

An 5kg object is 6 meters up hill. Find potential energy

Physics
2 answers:
Nataly_w [17]3 years ago
5 0
P=mgh
P= (5kg)(6m)(9.8m/sec2)
P=294 joul
Mila [183]3 years ago
4 0
Potential Energy = mass * 9.81 * height
(9.81 is the acceleration due to gravity on Earth)

PE = 6 * 9.81 * 6 = 353.16 J
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Answer:

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Explanation:

7 0
3 years ago
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A smooth circular hoop with a radius of 0.800 m is placed flat on the floor. A 0.300-kg particle slides around the inside edge o
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Answer:

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Explanation:

Given that

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m= 0.3 kg

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a)

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KE_i=\dfrac{1}{2}mu^2

KE_i=\dfrac{1}{2}0.3\times 10^2

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Final kinetic energy

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b)

The minimum value to complete the circular arc

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Now by putting the values

V=\sqrt{0.8\times 10}

V= 2.82 m/s

So kinetic energy KE

KE=\dfrac{1}{2}mV^2

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KE=1.19 J

ΔKE= KEi - KE

ΔKE= 15- 1.19 J

ΔKE=13.80 J

The minimum energy required to complete 2 revolutions = 2 x 11.25 J

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Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.

Number of revolution = 1

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3 years ago
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Answer:

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N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

8 0
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Answer:

i think its B

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