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igomit [66]
3 years ago
10

What types of intermolecular forces are collectively named van der waals forces after johannes van der waals, who developed the

equation for predicting the deviation of gases from ideal behavior?
Chemistry
1 answer:
gladu [14]3 years ago
6 0
Dispersion forces or London dispersion forces are collectively referred to as Van der Waals forces. These forces are temporary and arise from the relative position of electrons in one atom to another. If the electrons become distributed in an asymmetrical manner, the negative charge is concentrated at one end of the particle and a positive charge is concentrated at the other. These forces are also called induced dipole-induced dipole attraction.
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Which solution below yields the lowest final concentration of a sodium hydroxide solution prepared by diluting 50.00 mL of conce
Firdavs [7]

Answer:

The answer to your question is: letter D. 1.33 L

Explanation:

Data

V1 = 50 ml

C1 = 19.3

To solve this problem use the formula  C₁V₁ = C₂V₂

                            C2 = C1V1 / V2

C = concentration

V = volume

a) 1.15 L

                     C2 = (19.3)(50) / 1150

                      C2 = 0.84 M

b) No right answer

c) V2= 0.80 L

                     C2 = (19.3)(50) / 800

                     C2 = 1.2 M

d) V2 = 1.33 L

                        C2 = (19.3)(50) / 1330

                       C2 = 0.72 M

e) V2 = 350 ml

                         C2 = (19.3)(50) / 350

                         C2 = 2.75 M  

3 0
3 years ago
8). How many moles of oxygen gas must be placed in a 35.0 L container in order
klemol [59]

Answer:

4.1 moles

Explanation:

Applying

PV = nRT................ equation 1

Where P = pressure, V = volume, n = number of moles, R = molar gas constant, T = Temperature.

make n the subject  of the equation

n = PV/RT.............. Equation 2

From the question,

Given: V = 35 L , P = 2.8 atm, T = 15 °C  = (15+273) = 288 K, R = 0.083 L.atm/K.mol

Substitute these values into equation 2

n = (35×2.8)/(0.083×288)

n = 4.1 moles

5 0
3 years ago
Identify the variables in the investigation: An investigation was done with an electromagnetic system made from a battery and wi
kondaur [170]

Answer:

Independent: sizes of nails

Dependent: number of paper clips

Controlled: Battery, wire and type of nails

Explanation:

An independent variable is a variable which when changes does not the effect the results of the experiment. It does not depends upon the dependent variable.

A dependent variable is defined as a variable which is affected when the independent variable is changed by the researcher or the experimenter. It depends greatly upon the independent variable.

While a controlled variable is that variable whose value is not changed in an experiment. It contains all the constants.

In the context,

the independent variable are : sizes of nails

the dependent variables are : number of paper clips

the Controlled variables are: Battery, wire and type of nails

8 0
3 years ago
Consider two compounds. Compound A contains 15.7 g of sulfur and 18.6 g of fluorine. Compound B contains 25.4 g of sulfur and 60
Lunna [17]

Answer:

No, compound A and B are not the same compound

Explanation:

According to the law of definite proportion "every chemical compound contains fixed and constant proportions (by mass) of its constituent elements." (Encyclopedia Britannica)

We can see in the question that the ratio of flourine to sulphur in compound A is 1.18 while the ratio of flourine to sulphur in compound B is 2.37.

The two chemical compounds do not contain a fixed proportion by mass of their constituent elements therefore, they can not be same compound according to the law of definite proportions.

4 0
3 years ago
The gas SF6 is used to trace air flows because it is non-toxic and can be detected selectively in air at a concentration of 1.0
melomori [17]

SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.

First, we will calculate the partial pressure of SF₆  using the following expression.

pSF_6 = P \times \frac{ppb}{10^{9} }

where,

  • pSF₆: partial pressure of SF₆
  • P: total pressure of air (we will assume it is 1 atm)
  • ppb: concentration of SF₆ in parts per billion

pSF_6 = P \times \frac{ppb}{10^{9} } = 1 atm \times \frac{1.0 ppb}{10^{9} } = 1.0 \times 10^{-9} atm

Then, we will convert 1.0 cm³ to L using the following conversion factors:

  • 1 cm³ = 1 mL
  • 1 L = 1000 mL

1.0 cm^{3} \times \frac{1mL}{1cm^{3}} \times \frac{1L}{1000 mL} = 1.0 \times 10^{-3} L

Next, we will convert 46 °C to Kelvin using the following expression.

K = \° C + 273.15 = 46 + 273.15 = 319 K

Afterward, we calculate the moles (n) of sulfur hexafluoride using the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T}  = \frac{1.0 \times 10^{-9} atm  \times 1.0 \times 10^{-3} L}{(0.082 atm.L/mol.K) \times 319 K} = 3.8 \times 10^{-14} mol

Finally, we will convert 3.8 × 10⁻¹⁴ mol to molecules using Avogadro's number.

3.8 \times 10^{-14} mol \times \frac{6.02 \times 10^{23} molecules  }{mol} = 2.3 \times 10^{10} molecules

SF₆ in the air at a concentration of 1.0 ppb, exerts a partial pressure of 1.0 × 10⁻⁹ atm. At this concentration, 2.3 × 10¹⁰ molecules of SF₆ are contained in 1.0 cm³ of air at 46 °C.

You can learn more about partial pressure here: brainly.com/question/13199169

6 0
3 years ago
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