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stira [4]
3 years ago
5

A cart is moving to the right with a constant speed of 20 m s . A box of mass 80 kg moves with the cart without slipping. The co

efficient of static friction between the box and cart is 0.30, and the coefficient of kinetic friction between the box and cart is 0.15. What are the magnitude and direction of the frictional force acting on the box as it moves with the cart?
Physics
1 answer:
nignag [31]3 years ago
4 0

Answer:

Explanation:

Given

mass of box m=80 kg

coefficient of kinetic friction \mu _k=0.15

coefficient of Static friction \mu _s=0.30

cart is moving with constant velocity therefore Net Force is zero

Since there is no net acceleration therefore friction force will be zero

mathematically

f_r=ma

where f_r=frictional\ Force

a=acceleration

a=0

f_r=0

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<h3>What is Net force?</h3>

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

Given, Angela has a bucket of mass 2 kg tied to a string. She places a drinking glass of mass 0.5 kg in the bucket. She spins the bucket in a vertical circle of radius 1.5 m. She must swing the bucket to keep the glass from falling out.

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Fb = mVtop² /R

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T +mb xg - N =  mb x Vtop² /R..............(1)

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mg x g + N =  mg x Vtop² /R..............(2)

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T + (mb + mg) xg = (mb + mg) Vtop² /R

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Vtop = 4.99 m/s

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