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DENIUS [597]
3 years ago
13

A certain liquid has a vapor pressure of 92.0 Torr at 23.0 °C and 313.0 Torr at 45.0 °C. Calculate the value of ΔH°vap for this

liquid.
Chemistry
1 answer:
alexandr402 [8]3 years ago
4 0
<span>Given Data :

P 1=92 torr
P 2=313 
T 1=296 k
T 2=318 
</span><span>Hvap = 47900 Joules
</span>R=1.99 cal/mole-k <span>

Using </span><span>Clausius-Clapeyron equation :
</span>logP2/P1 = delta H/(2.303*R) * (1/T1-1/T2)

log 313/92=0.53
<span>2.303*R= 2.303*1.99
             = 4.5829 cal/mole-k
</span><span>1/T1-1/T2=1/296 - 1/318
</span>                =  0.0000233
<span>delta H = 0.53*4.5829/0.000233
 </span>delta <span>H </span><span>= 10424.622 cal</span>

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