The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.
<h3>
Acceleration of the car </h3>
The acceleration of the car before stopping at the given distance is calculated as follows;
v² = u² + 2as
when the car stops, v = 0
0 = u² + 2as
0 = 15² + 2(76.5)a
0 = 225 + 153a
-a = 225/153
a = - 1.47 m/s²
<h3>Distance traveled when the speed is 32 m/s</h3>
If the same force is applied, then acceleration is constant.
v² = u² + 2as
0 = 32² + 2(-1.47)s
2.94s = 1024
s = 348.3 m
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Answer:
1.5 m/s.
Explanation:
The Speed of a wave is the product of the wavelength and its frequency or it is the ratio of it wavelength and its Period. It can be expressed mathematically as
V = λf or λ/T .............................. Equation 1
Where V = speed of the wave travelling on the string, λ = wavelength of the wave, T = period of the wave, F = frequency of the wave.
Given: λ = 1.8 m ( distance it takes to repeat itself), T = 1.2 s (Time taken to complete a full cycle)
Substitute into equation 1
V = 1.8/1.2
V = 1.5 m/s.
Hence the wave is 1.5 m/s fast.
Answer:
JC⁻¹
Explanation:
= mass of water added to calorimeter = 94.8 g
= initial temperature of the water added = 60.4 C
= specific heat of water = 4.184 Jg⁻¹C⁻¹
= mass of water available to calorimeter = 94.8 g
= initial temperature of the water in calorimeter = 22.3 C
= final equilibrium temperature = 35 C
= Heat gained by calorimeter
Using conservation of heat
Heat gained by calorimeter = Heat lost by water added - heat gained by water in calorimeter
J
= Change in temperature of calorimeter
Change in temperature of calorimeter is given as
C
Heat capacity of calorimeter is given as
JC⁻¹
The answer would be B) 5 m/s^2. 45 m/s-5 m/s= 40 m/s so then 40 m/s divided by 8 s would be equal to 5 m/s^2
Explanation:
Gravitational potential energy
= mgh
= (2kg)(10N/kg)(5m)
= 100J.