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Tasya [4]
4 years ago
6

What relationships can be determined from a balanced chemical equation?

Chemistry
1 answer:
Kruka [31]4 years ago
8 0

Answer:

<em>From a balanced chemical equation the relationships </em><u>of the amount of reactants and products, either as number of units (moles) or as mass (grams), </u><em>can be determined. </em>

Explanation:

Since reactants combine in a fixed ratio to form a fixed amount of products, the law of mass conservation permits to state cuantitative relationships between the amounts of rectants and products, and this is represented through a balanced chemical equation.

The balanced chemical equation represents the reactants and products using the chemical composition of each substance (consisting of chemical symbols and subscritps)  and shows the relations in which they react or are produced using numbers as coefficients.

For example:

  • <em>Balanced chemical equation:</em> 1CH₄(g+ 2O₂(g) → 1CO₂(g) + 2H₂O(g)

  • <em>Relationships</em>:

       1 molecule CH₄ : 2 molecules O₂ : 1 molecule CO₂ : 2 molecules H₂O

       1 mole CH₄ : 2 moles O₂ : 1 mole CO₂ : 2 moles H₂O

       16.04 g CH₄ : 64.00 g O₂ : 44.01 g CO₂ : 36.03 g H₂O

        (80.04 g reactants = 80.04 g products)

     

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Naturally occurring zirconium exists are five isotopes. axe with a mass of 89.905 u(51.45%); Zr with a mass of 90.906 u (11.22%)
Anton [14]
Isotope 1: 89.905 * 51.45 = 4625.61225 / 100 = 46.2561225
Isotope 2: 90.906 * 11.22 = 1019.96532 / 100 = 10.1996532
Isotope 3: 91.905 * 17.15 = 1576.17175 / 100 = 15.7617075
Isotope 4: 93.906 * 17.38 = 1632.08628 / 100 = 16.3208628
Isotope 5: 95.908 * 2.08 = 268.5424 / 100 = 2.685424

46.2561225 + 10.1996532 +  15.7617075 + 16.3208628 + 2.685424 = 91.22377
actual mass Zr = about 91.22
8 0
4 years ago
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Ksivusya [100]

Answer:

A, C, D.

Explanation:

6 0
3 years ago
Read 2 more answers
What is a common reason for observing an increased chemical shift of a c-h proton
stira [4]

Deshielding due to an electronegative element close by is the common reason for observing increased chemical shift of a c-h proton

<h3>What is a chemical shift? </h3>

The resonance frequency of a proton in relation to a standard compound is represented by chemical shift. Chemical shift, which is measured in ppm and is represented by the sign (δ),  (parts per million).The chemical shift in a proton NMR spectrum provides details about the targeted proton's chemical surroundings. The structure of the investigated substance, especially electronegative components or effects, has a significant impact on the chemical shift value. Electronegative elements' ability to remove electron density from the proton, which raises the chemical shift value, is one explanation for this. The proton is more exposed to the magnetic field that is being applied externally as a result of this process, which is referred to as de-shielding.

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3 0
2 years ago
What is the preasure in atmospheres of 20 mol of nitrogen gas in 36.2 L cylinder at 25 degrees C?
Savatey [412]

Answer:

P = 13.5 atm

Explanation:

Given that

No. of moles, n = 20 moles

Volume of nitrogen gas = 36.2 L

Temperature = 25°C = 298 K

We need to find the pressure of the gas. Using the ideal gas equation

PV = nRT

Where

R is gas constant, R=0.082057\ L-atm/K-mol

So,

P=\dfrac{nRT}{V}\\\\P=\dfrac{20\times 0.082057\times 298}{36.2 }\\\\P=13.5\ atm

so, the pressure of the gas is equal to 13.5 atm.

7 0
3 years ago
72.0 grams of water how many miles of sodium with react with it?
Flura [38]

Answer:

\large \boxed{\text{8.00 mol}}

Explanation:

We will need a balanced chemical equation with masses, moles, and molar masses.

1. Gather all the information in one place:

Mᵣ:                  18.02

            2Na + H₂O ⟶ 2NaOH + H₂

m/g:                72.0  

2. Moles of H₂O

\text{Moles of H$_{2}$O} = \text{72.0 g H$_{2}$O} \times \dfrac{\text{1 mol H$_{2}$O}}{\text{18.02 g  H$_{2}$O}} = \text{3.996 mol H$_{2}$O}

3. Moles of Na

The molar ratio is 2 mol Na/1 mol H₂O.

\text{Moles of Na} =  \text{3.996 mol H$_{2}$O} \times \dfrac{\text{2 mol Na}}{\text{1 mol H$_{2}$O}} = \textbf{8.00 mol Na}\\\\\text{The water will react with $\large \boxed{\textbf{ 8.00 mol}}$ of Na}

7 0
3 years ago
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