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3 years ago

Number 8 please. die tomorrow. ASAP

Physics

2 answers:

Nookie1986 [14]3 years ago

7 0

A- 85m per second
B- 85 sdcounds

Alex_Xolod [135]3 years ago

6 0

Use the energy relation mgh = (1/2)mv². Divide out mass, m to get
gh = v²/2 or v = √2gh

This relates the gravitational potential energy (GPE) to the kinetic energy (KE). If the ball is 85 meters up, that's h. g is 9.81m/s² (access due to gravity)
v= 40.84m/s
Its time to hit the ground can be found by integrating the acceleration twice to get the vertical position function: y = (9.81/2)·t². Since y must equal 85:
85=(9.81/2)·t² ; 17.33 = t² ; t = √17.33 = 4.16s

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Fission is the process of creating energy by

Colt1911 [192]

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Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.

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3 0

3 years ago

a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro

finlep [7]

Answer:

$\theta=53.13^o$

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

$V_x=V_{ox}=V_ocos\theta$

$V_y=V_{oy}-gt=V_osin\theta-gt$

$x=V_{ox}t$

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}$

$\displaystyle y_{max}=\frac{V_{oy}^2}{2g}$

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

$x_{max}=3y_{max}$

$\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}$

Using the formulas for $V_{ox}, V_{oy}:$

$\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}$

Simplifying

$4cos\theta sin\theta=3sin^2\theta$

Dividing by $sin\theta$

$4cos\theta=3sin\theta$

Rearranging

$tan\theta=\frac{4}{3}$

$\theta=arctan\frac{4}{3}$

$\theta=53.13^o$

4 0

4 years ago

How would the moon appear from Earth if the moon did not rotate?

andrey2020 [161]

It would mean that only one side of earth would be light and the other dark all the time also we would only see the sun on one side and on the other we see the moon

6 0

3 years ago

Read 2 more answers

What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at

romanna [79]

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

= 100 / 1

100 cc

1 / 10 litres.

6 0

3 years ago

Spesifikasi solder listrik 220 volt/60 watt. solder tersebut dipasang pada tegangan 110 volt. daya ada solder listrik tersebut a

Katarina [22]

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3 0

3 years ago