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Anastaziya [24]
3 years ago
12

How fast is a 180 kg motorcycle traveling if it has 36000 J of kinetic energy??

Physics
1 answer:
leva [86]3 years ago
7 0

Answer:

20 ms⁻¹

360 J

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. =  (1/2)mv² where all terms in usual meaning

So you get,

K.E. = 36000 =  (1/2)×180×v²

v = 20 ms⁻¹

Also,

K.E. =  (1/2)×80×3² = 360 J

   

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Given:
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T^2=Dy/(1/2)A
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Consider a parachutist that has reached terminal velocity. which of the following is true? A.) The acceleration of the parachuti
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Yakvenalex [24]

Answer:

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You are on a 4 m high ladder and throw a ball upwards at 12 m/s. It lands on the ground below the ladder.
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a) 2.75 s

The vertical position of the ball at time t is given by the equation

y= h+ut-\frac{1}{2}gt^2

where

h = 4 m is the initial height of the ball

u = 12 m/s is the initial velocity of the ball (upward)

g = 9.8 m/s^2 is the acceleration of gravity (downward)

We can find the time t at which the ball reaches the ground by substituting y=0 into the equation:

0 = 4 + 12t - 4.9 t^2

This is a second-order equation. By solving it for t, we find:

t = -0.30 s

t = 2.75 s

The first solution is negative, so we discard it; the second solution, t = 2.75 s, is the one we are looking for.

b) -15.0 m/s (downward)

The final velocity of the ball can be calculated by using the equation:

v=u-gt

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u = 12 m/s is the initial (upward) velocity

g = 9.8 m/s^2 is the acceleration of gravity (downward)

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And the negative sign means the direction is downward.

7 0
3 years ago
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