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3 years ago

How fast is a 180 kg motorcycle traveling if it has 36000 J of kinetic energy??

Physics

1 answer:

leva [86]3 years ago

7 0

Answer:

20 ms⁻¹

360 J

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. = (1/2)mv² where all terms in usual meaning

So you get,

K.E. = 36000 = (1/2)×180×v²

v = 20 ms⁻¹

Also,

K.E. = (1/2)×80×3² = 360 J

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Aloiza [94]

Answer:

The answer to your question is letter A. r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

$F = K\frac{q1q2}{r^{2}}$

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$r = \sqrt{\frac{kq1q2}{F}}$

Substitution

$r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}$

Simplification

r = $\sqrt{\frac{2.3 x 10^{-28}}{2}}$

r = $\sqrt{1.15 x 10^{-24}}$

Result

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3 years ago

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xxTIMURxx [149]

Answer:

1985kg

Explanation:

assuming that

pi =3.14

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3 years ago

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My name is Ann [436]

Answer:

Relation between initial speed of bullet and height h is given as

$v = \frac{m + M}{m}\sqrt{2gh}$

Explanation:

As we know that system of block and bullet swings up to height h after collision

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$mv = (m + M)v_1$

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