Answer:
23.49m
Explanation:
Distance = velocity x time
8.7 x 2.7 = 23.49m
Answer: 
Explanation:
If we make an analysis of the net force
of the rock that was thrown upwards, we will have the following:
(1)
Where:
is the force with which the rock was thrown
is the weight of the rock
Being the weight the relation between the mass
of the rock and the acceleration due gravity
:
(2)
(3)
Substituting (3) in (1):
(4)
(5) This is the net Force on the rock
On the other hand, we know this force is equal to the multiplication of the mass with the acceleration, according to Newton's 2nd Law:
(6)
Finding the acceleration
:
(7)
(8)
Finally:
Answer:
342,000kg
Explanation:
p=mv
8.55*10^7 kg*m/s=m(900 km/h)
85,500,000 kg*m/s=m(900 km/h)
(85,500,000 kg*m/s)/(900 km/h)=m
Get same units.... 900km/h = 250m/s
m/s cancel in the division, you are left with just kg!!
85,500,000/250=342,000kg! That's it!
Answer:
The moment of inertia about an axis through the center and perpendicular to the plane of the square is

Explanation:
From the question we are told that
The length of one side of the square is 
The total mass of the square is 
Generally the mass of one size of the square is mathematically evaluated as

Generally the moment of inertia of one side of the square is mathematically represented as

Generally given that
it means that this moment inertia evaluated above apply to every side of the square
Now substituting for 
So

Now according to parallel-axis theorem the moment of inertia of one side of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as
![I_a = I_g + m [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20m%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> ![I_a = I_g + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20I_g%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
substituting for 
=> ![I_a = \frac{1}{12} * \frac{M}{4} * a^2 + {\frac{M}{4} }* [\frac{q}{2} ]^2](https://tex.z-dn.net/?f=I_a%20%3D%20%20%5Cfrac%7B1%7D%7B12%7D%20%20%2A%20%20%5Cfrac%7BM%7D%7B4%7D%20%2A%20a%5E2%20%2B%20%7B%5Cfrac%7BM%7D%7B4%7D%20%7D%2A%20%5B%5Cfrac%7Bq%7D%7B2%7D%20%5D%5E2)
=> 
=> 
Generally the moment of inertia of the square about an axis through the center and perpendicular to the plane of the square is mathematically represented as

=> 
=> 