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Scilla [17]
3 years ago
8

A) A 5.00-kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0 m/s. What is the recoil velocity of the sq

uid if the ejection is done in 0.100 s and there is a 5.00-N frictional force opposing the squid’s movement?
(b) How much energy is lost to work done against friction?
Physics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

(a) The recoil velocity of the squid is 0.5 m/s

(b) W = 0.25 J

Explanation:

(a)

Momentum of the squid = momentum of the fluid

MV = mv

Where M = mass of the squid, V = recoil velocity of the squid, m = mass of the  fluid, v = recoil velocity of the fluid.

Making V the subject of formula,

V = mv/M

Where m = 0.25 kg, M = 5.00 kg, v = 10 m/s

V = (0.25 × 10)/5

V = 0.5 m/s

The recoil velocity of the squid is 0.5 m/s

(b)

Work done against friction (W) = Frictional force(F) × Distance(d)

W = F ×d.................... Equation 2

Where F = 5.0N, d = distance.

d = velocity × time

Where Velocity = 0.5 m/s, Time = 0.1 s

∴ d = 0.5 × 0.1 = 0.05 m

Substituting these values into equation 2,

W = 5 × 0.05

W = 0.25 J

Therefore 0.25 J of energy is lost to the work done against friction.

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Estimate the volume of a piece of molecular cloud that has the same amount of water as your body.
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Question:

The water molecules now in your body were once part of a molecular cloud. Only about onemillionth of the mass of a molecular cloud is in the form of water molecules, and the mass density of such a cloud is roughly 2.0×10−21 g/cm^3.

Estimate the volume of a piece of molecular cloud that has the same amount of water as your body.

Answer:

The volume of cloud that has the same density as the amount of water in our body is 1.4×10²⁵ cm³

Explanation:

Here, we have mass density of cloud  =  2.0×10⁻²¹ g/cm^3

Density = Mass/Volume

Volume = Mass/Density =   If the mass is 40 kg and the body is made up of 70% by mass of water, we have

28 kg water = 28000 g

Therefore the Volume = 28 kg/ 2.0×10⁻²¹ g/cm^3 = 1.4×10¹⁹ m³ = 1.4×10²⁵ cm³.

Therefore, the volume of cloud that has the same density as the amount of water in our body = 1.4×10²⁵ cm³.

6 0
3 years ago
a machine with a mechanical advantage of 2.5 requires an input force of 120 newtons. What output force is applied by this machin
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If your machine has a mechanical advantage of 2.5, then WHATEVER force you apply to the input, the force at the output will be 2.5 times as great.

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                 (2.5 x 1 newton)  =  2.5 newtons.

If you apply 120 newtons to the machine's input, the output force is

                 (2.5 x 120 newtons)  =  300 newtons.

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Belly-flop Bernie dives from atop a tall flagpole into a swimming pool below. His potential energy at the top is 7000 J (relativ
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Answer:

KE₂ = 6000 J

Explanation:

Given that

Potential energy at top U₁= 7000 J

Potential energy at bottom U₂= 1000 J

The kinetic energy at top ,KE₁= 0 J

Lets take kinetic energy at bottom level =  KE₂

Now from energy conservation

U₁+ KE₁= U₂+ KE₂

Now by putting the values

U₁+ KE₁= U₂+ KE₂

7000+ 0 = 1000+ KE₂

KE₂ = 7000 - 1000 J

KE₂ = 6000 J

Therefore the kinetic energy at bottom is 6000 J.

5 0
3 years ago
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