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Scilla [17]
3 years ago
8

A) A 5.00-kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0 m/s. What is the recoil velocity of the sq

uid if the ejection is done in 0.100 s and there is a 5.00-N frictional force opposing the squid’s movement?
(b) How much energy is lost to work done against friction?
Physics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

(a) The recoil velocity of the squid is 0.5 m/s

(b) W = 0.25 J

Explanation:

(a)

Momentum of the squid = momentum of the fluid

MV = mv

Where M = mass of the squid, V = recoil velocity of the squid, m = mass of the  fluid, v = recoil velocity of the fluid.

Making V the subject of formula,

V = mv/M

Where m = 0.25 kg, M = 5.00 kg, v = 10 m/s

V = (0.25 × 10)/5

V = 0.5 m/s

The recoil velocity of the squid is 0.5 m/s

(b)

Work done against friction (W) = Frictional force(F) × Distance(d)

W = F ×d.................... Equation 2

Where F = 5.0N, d = distance.

d = velocity × time

Where Velocity = 0.5 m/s, Time = 0.1 s

∴ d = 0.5 × 0.1 = 0.05 m

Substituting these values into equation 2,

W = 5 × 0.05

W = 0.25 J

Therefore 0.25 J of energy is lost to the work done against friction.

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What is the formula that describes the magnitude of impulse on an object?
vladimir1956 [14]

Answer:

Option C.

Impulse = mass × change in velocity

Explanation:

Impulse is defined by the following the following formula:

Impulse = force (F) × time (t)

Impulse = Ft

From Newton's second law of motion,

Force = change in momentum /time

Cross multiply

Force × time = change in momentum

Recall:

Impulse = Force × time

Thus,

Impulse = change in momentum

Recall:

Momentum = mass x velocity

Momentum = mv

Chang in momentum = mass × change in velocity

Change in momentum = mΔv

Thus,

Impulse = change in momentum

Impulse = mass × change in velocity

8 0
3 years ago
Except for the nodes on a standing wave, what is the frequency f of the points executing simple harmonic motion?
Katen [24]

Take into account that in a standing wave, the frequency f of the points executing simple harmonic motion, is simply a multiple of the fundamental harmonic fo, that is:

f = n·fo

where n is an integer and fo is the first harmonic or fundamental.

fo is given by the length L of a string, in the following way:

fo = v/λ = v/(L/2) = 2v/L

becasue in the fundamental harmonic, the length of th string coincides with one hal of the wavelength of the wave.

6 0
1 year ago
What is the volume V of a sample of 4.00 mol of copper? The atomic mass of copper (Cu) is 63.5 g/mol, and the density of copper
rusak2 [61]

Answer : The volume of a sample of 4.00 mol of copper is 28.5cm^3

Explanation :

First we have to calculate the mass of copper.

\text{ Mass of copper}=\text{ Moles of copper}\times \text{ Molar mass of copper}

\text{ Mass of copper}=(4.00moles)\times (63.5g/mole)=254g

Now we have to calculate the volume of copper.

Formula used :

Density=\frac{Mass}{Volume}

Now put all the given values in this formula, we get:

8.92\times 10^3kg/m^3=\frac{254g}{Volume}

Volume=\frac{254g}{8.92\times 10^3kg/m^3}=2.85\times 10^{-2}L=2.85\times 10^{-2}\times 10^3cm^3=28.5cm^3

Conversion used :

1kg/m^3=1g/L\\\\1L=10^3cm^3

Therefore, the volume of a sample of 4.00 mol of copper is 28.5cm^3

7 0
3 years ago
Read 2 more answers
Mechanical waves can travel through _______.
eimsori [14]

mediums only, mechanical waves always propagate through medium

5 0
3 years ago
Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis
Stella [2.4K]

Answer:

v_x = 4.87 m/s

Explanation:

Height of the cliff is given as

h = 37.1 m

now the time taken by the diver to hit the surface is given as

h = \frac{1}{2}gt^2

37.1 = \frac{1}{2}(9.8)t^2

t = 2.75 s

Now in the same time it has to cover a distance of 13.39 m

so the speed in horizontal direction is given as

v_x = \frac{x}{t}

v_x = \frac{13.39}{2.75}

v_x = 4.87 m/s

3 0
3 years ago
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