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mamaluj [8]
3 years ago
5

What is one advantage of doing a field experiment instead of a laboratory experiment

Physics
1 answer:
Flauer [41]3 years ago
5 0

It mimics the real world accurately

Explanation:

Experiments conducted in the field clearly presents the real world at it is to the scientist. Hardly can any part be controlled precisely and this gives a near to perfect scenario.

  • In the laboratory, for example, an organism is isolated from its environment and might not fully display its natural instinct and physiological capabilities.
  • Most laboratory set up are driven towards a model instead of real life settings.
  • The laboratory is more controlled and less varied and might truly represent the real world. It will only portray a part of the real world and series of further tests might have to be carried out to have a better model.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

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Which of the following is equal to 1W?<br><br>A.1 J<br>B.1 J/s<br>C.1 J·s<br>D.1 N·m
Ray Of Light [21]
B. Extra text to get to 20 characters.
7 0
3 years ago
A force in the +x-direction with magnitude ????(x) = 18.0 N − (0.530 N/m)x is applied to a 6.00 kg box that is sitting on the ho
fiasKO [112]

Answer:

v_f=8.17\frac{m}{s}

Explanation:

First, we calculate the work done by this force after the box traveled 14 m, which is given by:

W=\int\limits^{x_f}_{x_0} {F(x)} \, dx \\W=\int\limits^{14}_{0} ({18N-0.530\frac{N}{m}x}) \, dx\\W=[(18N)x-(0.530\frac{N}{m})\frac{x^2}{2}]^{14}_{0}\\W=(18N)14m-(0.530\frac{N}{m})\frac{(14m)^2}{2}-(18N)0+(0.530\frac{N}{m})\frac{0^2}{2}\\W=252N\cdot m-52N\cdot m\\W=200N\cdot m

Since we have a frictionless surface, according to the the work–energy principle, the work done by all forces acting on a particle equals the change in the kinetic energy of the particle, that is:

W=\Delta K\\W=K_f-K_i\\W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}

The box is initially at rest, so v_i=0. Solving for v_f:

v_f=\sqrt{\frac{2W}{m}}\\v_f=\sqrt{\frac{2(200N\cdot m)}{6kg}}\\v_f=\sqrt{66.67\frac{m^2}{s^2}}\\v_f=8.17\frac{m}{s}

5 0
3 years ago
You have a set of calipers that can measure thicknesses of a few inches with an uncertainty of ± 0.005 inches. You measure the t
Bond [772]

Answer:

a) x = (0.0114 ± 0.0001) in , b) the number of decks is 5

Explanation:

a) The thickness of the deck of cards (d) is measured and the thickness of a card (x) is calculated

        x = d / 52

        x = 0.590 / 52

        x = 0.011346 in

Let's look for uncertainty

       Δx = dx /dd Δd

       Δx = 1/52 Δd

       Δx = 1/52  0.005

       Δx = 0.0001 in

The result of the calculation is

        x = (0.0114 ± 0.0001) in

b) You want to reduce the error to Δx = 0.00002, the number of cards to be measured is

           #_cards = n 52

The formula for thickness is

           x = d / n 52

Uncertainty

          Δx = 1 / n 52  Δd

         n = 1/52 Δd / Δx

         n = 1/52 0.005 / 0.00002

         n = 4.8

Since the number of decks must be an integer the number of decks is 5

3 0
3 years ago
6. Mr. Leppold jumps out of a plane with a parachute...before the chute opens,
polet [3.4K]

1) He has both potential and kinetic energy

2) Before the parachute opens, the potential energy decreases and the kinetic energy increases

Explanation:

1)

The gravitational potential energy of a body is the energy possessed by the object due to its position in a gravitational field, and it is given by:

PE=mgh

where

m is the mass of the body

g is the acceleration of gravity

h is the height of the body above the ground

On the other hand, the kinetic energy of a body is the energy possessed by the body due to its motion; it is given by

KE=\frac{1}{2}mv^2

where

v is the speed of the object

Here Mr. Leppold has both potential and kinetic energy before opening the parachute, because:

- It is moving at a certain speed, so v\neq 0, therefore he has kinetic energy

- He is at a certain height above the ground, h\neq 0, therefore he has potential energy

2)

The total mechanical energy of Mr.Leppold is the sum of the potential and the kinetic energy:

E=PE+KE

According to the law of conservation of energy, in absence of air resistance, this quantity remains constant.

During the fall, the height of Leppold decreases: this means that as h decreases, the potential energy decreases  too.

However, the total energy E must remain constant: therefore, this means that the kinetic energy KE must increase, and this occurs because the speed of Mr. Leppold increases as he falls.

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

8 0
3 years ago
A calorimeter has a heat capacity of 1265 J/oC. A reaction causes the temperature of the calorimeter to change from 22.34oC to 2
Ray Of Light [21]
<h2>Heat released in this process is 3516.7 J</h2>

Explanation:

A calorimeter has a heat capacity of 1265 J/°C

Heat capacity of calorimeter = 1265 J/°C

A reaction causes the temperature of the calorimeter to change from 22.34°C to 25.12°C

Change in temperature = 25.12 - 22.34 = 2.78°C

Heat released = Heat capacity of calorimeter x Change in temperature

Heat released = 1265 x 2.78 = 3516.7 J

Heat released in this process is 3516.7 J

5 0
3 years ago
Read 2 more answers
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