All categories

3 years ago

What is one advantage of doing a field experiment instead of a laboratory experiment

Physics

1 answer:

Flauer [41]3 years ago

5 0

It mimics the real world accurately

Explanation:

Experiments conducted in the field clearly presents the real world at it is to the scientist. Hardly can any part be controlled precisely and this gives a near to perfect scenario.

In the laboratory, for example, an organism is isolated from its environment and might not fully display its natural instinct and physiological capabilities.
Most laboratory set up are driven towards a model instead of real life settings.
The laboratory is more controlled and less varied and might truly represent the real world. It will only portray a part of the real world and series of further tests might have to be carried out to have a better model.

Learn more:

Experiment brainly.com/question/5096428

#learnwithBrainly

You might be interested in

A 762 kg car experiences a braking force of 9045 N and skids to a stop in 4.3 seconds. What is the speed of the car just before

PilotLPTM [1.2K]

Answer:

The solution for this problem is:

We will be using the formula for force which is F = ma

=>10,000 = 2000 * a

but we need to solve for acceleration so divide both sides by 2000, we will get:

=>a = 5 m/s^2

Let the initial velocity was u m/s

=>By v = u - at

=>0 = u - 5 x 6

Since acceleration is constant the velocity can be computed by multiplying the acceleration by 6 seconds.

=>u = 30 m/s

Explanation:

6 0

2 years ago

An airplane flies horizontally with a constant speed of 155.0 m/s at an unknown altitude. A package is released out of the airpl

vladimir1956 [14]

Answer:

y₀ = 1020.3 m

Explanation:

This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.

y = y₀ + $v_{oy}$ t - ½ g t²

when it reaches the ground its height is zero

0 = y₀ + 0 - ½ g t²

y₀ = ½ g t²

let's calculate

y₀ = ½ 9.8 14.43²

y₀ = 1020.3 m

8 0

2 years ago

According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f

Bond [772]

Answer:

$S_{s}=300 m/s$

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

Explanation:

In order to use the rule of thumb to find the speed of sound in meters per second, we need to use some conversion ratios. We know there is 1 mile per every 5 seconds after the lightning is seen. We also know that there are 5280ft in 1 mile and we also know that there are 0.3048m in 1ft. This is enough information to solve this problem. We set our conversion ratios like this:

$\frac{1mi}{5s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}=321.87m/s$

notice how the ratios were written in such a way that the units got cancelled when calculating them. Notice that in one ratio the miles were on the numerator of the fraction while on the other they were on the denominator, which allows us to cancel them. The same happened with the feet.

The problem asks us to express the answer to one significant figure so the speed of sound rounds to 300m/s.

For the second part of the problem we need to use conversions again. This time we will write our ratios backwards and take into account that there are 1000m to 1 km, so we get:

$\frac{5s}{1mi}*\frac{1mi}{5280ft}*\frac{1ft}{0.3048m}*\frac{1000m}{1km}=3.11s/km$

This means that for every 3.11s there will be a distance of 1km from the place where the lightning stroke. Since this is a rule of thumb, we round to the nearest integer for the calculations to be made easily, so the rule goes like this:

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

3 0

2 years ago

A solenoid has a radius Rs = 14.0 cm, length L = 3.50 m, and Ns = 6500 turns. The current in the solenoid decreases at the rate

babymother [125]

Answer:

E = 58.7 V/m

Explanation:

As we know that flux linked with the coil is given as

$\phi = NBA$