Answer:
The grating spacing of the beetle is 
Explanation:
The concept to solve this problem is relate to interference effect given in the Young's Slits. Here was demonstrated that the length of the side labelled \lambda is known as the path difference. The equation is given by,
Where,
= wavelenght of light
N = a positive integer: 1,2,3...
= Angle from the center of the wall to the dark spot
d= width of the slit
Replacing our values we have that for n=1,
Therefore the grating spacing of the beetle is
Answer:
0.37 m/s to the left
Explanation:
Momentum is conserved. Initial momentum = final momentum.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
Initially, both the fisherman/boat and the package are at rest.
0 = m₁ v₁ + m₂ v₂
Plugging in values and solving:
0 = (82 kg + 112 kg) v + (15 kg) (4.8 m/s)
v = -0.37 m/s
The boat's velocity is 0.37 m/s to the left.
A reasonable estimate for the height of the walls in an ordinary American home is 2.5m.
<h3>What is wall estimation?</h3>
Building gauge is of two sorts one is known as Rough Cost Estimate. This gauge won't depict the specific expense of the structure, however it can provide you with the rough expense worth of the structure that will help adequately in overseeing cash for the structure. Harsh Cost Estimate is directed in various ways for various sort of structures. The rough complete wall length is found in running meters in this framework and this all out length accumulated by the rate per running meter of the wall gives an actually solid cost. Assessment hypothesis is a part of insights that arrangements with assessing the upsides of boundaries in light of estimated experimental information that has an irregular part. The boundaries depict a fundamental actual setting so that their worth influences the circulation of the deliberate information.
Learn more about wall estimation, visit
brainly.com/question/17555311
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Part a:
= 56
= 60
= 63
The quartiles are found by finding the medium of the data, and then the mediums of the two different data sets on either side of the medium. The is the overall medium, is the medium of the first half, and is the medium of the second half.
-> How is the medium found? When finding the medium we put the values in order least to greatest and pick the middle value.
[] See attached
Part b:
The range is 7.
The interquartile range is the range of numbers between and . In other words, it is 50% of the data, directly in the middle.
This becomes 63 - 56 = 7
Part c:
79 is an outlier.
It is an outlier because it is 1.5 above or below (in this case, above) the interquartile range.
-> 63 + (7 + 
) ≤ 79
-> 63 + 10.5 ≤ 79
-> 73.5 ≤ 79
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.
- Heather
