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Harlamova29_29 [7]
3 years ago
11

Find the mass by adding the numbers from the three sliders

Physics
1 answer:
shtirl [24]3 years ago
3 0

add the numbers from the three sliders to determine that mass of an object


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Helpppppppp<br> ill give brainliest
Nina [5.8K]

Answer:

I believe the answer is

B. \: 3 \: red, \: 8 \: yellow, \: 1 \: blue

Explanation:

I may be incorrect because I used to do this a long time ago but I believe I am correct

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4 0
3 years ago
A planet orbits a star in an elliptical orbit. At a particular instant the momentum of the planet is
Masja [62]

Answer:

L = m v r (The momentum remains constant)

Explanation:

Even in an ellipsoidal orbit, the law of conservation of angular momentum always apply. When the plant approached the perihelion, the radius of the orbit decreases and the speed of the star increases to conserve the momentum. Similarly, when the planet approaches the aphelion, the speed of the star decreases as the radius increases to conserve the momentum. So, the momentum at a particular instant can be calculated by L = m v r

7 0
3 years ago
Neglecting air resistance which of the following statements is not true regarding the motion of a ball thrown vertically with an
inysia [295]

Answer:

c or b

Explanation:

6 0
3 years ago
) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th
Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

    m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w

Now, we will substitute 0 for both z_{1} and z_{2}, 0 for w, 334.9 kJ/kg for h_{1}, 2726.5 kJ/kg for h_{2}, 5 m/s for V_{1} and 220 m/s for V_{2}.

Putting the given values into the above formula as follows.

     m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w  

     1 \times [334.9 \times 10^{3} J/kg + \frac{(5 m/s)^{2}}{2} + 0] + q = 1 \times [2726.5 \times 10^{3} + \frac{(220 m/s)^{2}}{2} + 0] + 0

                q = 6597.711 kJ

Thus, we can conclude that heat transferred through the coil per unit mass of water is 6597.711 kJ.

6 0
4 years ago
A metric unit of volume
dsp73
A metric unit of volume is centermetres or metres, cubed e.g. Cm3
6 0
4 years ago
Read 2 more answers
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