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masha68 [24]
3 years ago
8

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then,

explain how you determined the number of each type of particle. Use the periodic table to help you.
Chemistry
2 answers:
kolezko [41]3 years ago
7 0

Answer:

Number of proton is 11

Number of neutrons is 12

Number of electrons is 10

Explanation:

For a neutral Na, Sodium atom:

The mass number P+N = 23

Atomic number(E or P) = 11

A charged Na atom that has lost an electron is positively charged and so:

Number of proton = 11 (Still the same)

Number of neutrons = 12

Number of electrons = 11-1=10 (the atom has lost an electron)

If an atom loses electron, it becomes positively charged ie P>E

AVprozaik [17]3 years ago
5 0

Answer:

It contains 11 protons in the nucleus.

It contains 12 neutrons in the nucleus.

It contains 10 electrons surrounding the nucleus.

The number of electrons are calculated from net charge and charge of proton (+1) and electron (–1).

12 neutrons are calculated from atomic number: 11 and mass number: 23.

Explanation:

These are the answers for Edu

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Write the formula of the first 5 members in the series of alkynes​
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5 0
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Consider the formation of nitrogen dioxide and oxygen: NO(g)+O3(g)⇌NO2(g)+O2(g) The reaction is first order in O3 and second ord
Leno4ka [110]

Answer:

The rate law is rate = k[NO][O₃]

Option E) is the right answer.

Explanation:

Hi there!

For this generic reaction:

A + B → products

the rate law will be:

rate = k[A]ⁿ[B]ᵃ

this reaction is n-order in A and a-order in B. The overall reaction is the sum of the orders of each reactant, in this case:

Overall order of the reaction = n + a

In our problem, we know that the reaction is first order in O₃ and second order overall. Then:

Overall order of the reaction = Order in NO + Order in O₃

2 = n + 1

2 - 1 = n

n = 1

Then, the reaction is first order in NO and first order in O₃.

The rate law will be:

rate = k[NO][O₃]

The right answer is the option E).

3 0
3 years ago
What is the molarity of 50.84 g of Na2CO3 dissolved in 0.400 L solution?
borishaifa [10]

Answer:

1.20 M

Explanation:

Convert grams of Na₂CO₃ to moles.  (50.84 g)/(105.99 g/mol) = 0.4797 mol

Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M

4 0
3 years ago
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