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3 years ago

1. A limiting factor for using nuclear energy is the

Physics

2 answers:

Goryan [66]3 years ago

8 0

Answer:

waste

Explanation:

took da test. nhgvgg

Arturiano [62]3 years ago

3 0

Pollutiondfffgggcffff fffffg

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The humidity you feel in the southern states of the U.S. is _____. part of the water cycle water vapor caused by the Sun's heat

Likurg_2 [28]

Hey there!

The answer is :
The <span>humidity you feel in the southern states of the U.S. is water vapor
water vapor is between a gas and liquid so that is what gives a humid feel in the hot sun

Hopes this helps u :D</span>

4 0

2 years ago

What is the difference between muscular endurance and muscular strength? A B or C

Galina-37 [17]

Answer:

Muscular endurance is how many times you can move a weight without getting tired.

Muscular strength is the amount force you can put out.

7 0

3 years ago

What is the stretch when you pull with a force of 25 N on a spring with a spring constant of 8 N/m? *

Pani-rosa [81]

Hooke's Law

$\tt F=k.\Delta x$

k = spring constant

x = stretch

F = force

Input the value

$\tt \Delta x=\dfrac{F}{k}=\dfrac{25}{8}=3.125\rightarrow 3.13\:m$

7 0

2 years ago

The brightness of a light bulb is most closely related to

vlada-n [284]

Answer:

a ) Its resistance

Explanation:

It depends on current and resistance

4 0

2 years ago

A 0.260 m radius, 525 turn coil is rotated one-fourth of a revolution in 4.17 ms, originally having its plane perpendicular to a

Sophie [7]

Answer:

B = 0.37T

Explanation:

In order to calculate the needed magnitude of the magnetic force you use the following formula, which calculate the induced emf of the solenoid when there is a change in the magnetic flux:

$emf=-N\frac{\Delta \Phi_B}{\Delta t}=-N\frac{\Delta (BAcos\theta)}{\Delta t}$ (1)

emf: induced voltage in the solenoid = 10,000V

N: turns of the solenoid = 525

ФB: magnetic flux

B: magnitude of the magnetic field = ?

A: cross-sectional area of the solenoid = π*r^2

r: radius of the cross-sectional area = 0.260m

Δt: interval time of the change of the magnetic flux = 4.17ms = 4.17*10^-3s

First, you have the magnetic field direction perpendicular to the plane of the solenoid, after, the angle between them is 90° (quarter of a revolution)

In the equation (1) the only parameter that changes on time is the angle, then, you can solve for B from the equation (1):

$emf=-NBA\frac{cos(90\°)-cos(0\°)}{\Delta t}=\frac{NBA}{\Delta t}\\\\B=\frac{(\Delta t)(emf)}{NA}=\frac{(\Delta t)(emf)}{N(\pi r^2)}\\\\$

Finally, you replace the values of the parameters to calculate B:

$B=\frac{(4.17*10^{-3}s)(10000V)}{(525)(\pi(0.260m)^2)}=0.37T$

The strength of the magnetic field is 0.37T

7 0

2 years ago