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Dennis_Churaev [7]
3 years ago
13

1. A limiting factor for using nuclear energy is the

Physics
2 answers:
Goryan [66]3 years ago
8 0

Answer:

waste

Explanation:

took da test. nhgvgg

Arturiano [62]3 years ago
3 0
Pollutiondfffgggcffff fffffg
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Two spacecraft are both 10 million kilometers from a star. The total power output of the star is 4 x 1025 W. Spacecraft 1 has a
Ksenya-84 [330]

The concept of power is given by the relationship between intensity and area, that is to say that power is defined as

P = A*I

Our values are given under the condition of,

r_1 = 18m

r_2 = m

The power is proportional to the Area, and in turn, we know that the Area of a circle is the product between \pi  times the radius squared, therefore the power is proportional to the radius squared.

\text{Power} \propto r^2

For both panels we would have to

\frac{\text{Power by panel 1}}{\text{Power by panel 2}} = \frac{r_1^2}{r_2^2}

\frac{P_1}{P_2} = (\frac{18}{6})^2

\frac{P_1}{P_2} = 9

Therefore the correct option is option C.9

5 0
3 years ago
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Which equation could not be used to determine straight line acceration?
uranmaximum [27]

Answer:

the answer for the question is the last option

5 0
3 years ago
Using an inclined plane, what happens to the amount of work that has to be done?
weeeeeb [17]
A. The amount of work increases.
Imagine you are pushing a box on a flat surface. Now imagine pushing it up a steep hill. It gets harder and that's how I remember this.
Hope this helps. 
8 0
3 years ago
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Kepler-62e is an exoplanet that orbits within the habitable zone around its parent star. The planet has a mass that is 3.57 time
skad [1K]

Answer:

g' = 13.5 m/s²

Explanation:

The acceleration due to gravity on surface of earth is given by the formula:

g = GMe/Re²   --------------- euation 1

where,

g = acceleration due to gravity on surface of earth

G = Universal Gravitational Constant

Me = Mass of Earth

Re = Radius of Earth

Now, the the acceleration due to gravity on the surface of Kepler-62e is:

g' = GM'/R'²   --------------- euation 1

where,

g' = acceleration due to gravity on surface of Kepler-62e

G = Universal Gravitational Constant

M' = Mass of Kepler-62e = 3.57 Me

R' = Radius of Kepler-62e = 1.61 Re

Therefore,

g' = G(3.57 Me)/(1.61 Re)²

g' = 1.38 GMe/Re²

using equation 1:

g' = 1.38 g

where,

g = 9.8 m/s²

Therefore,

g' = 1.38(9.8 m/s²)

<u>g' = 13.5 m/s²</u>

6 0
3 years ago
Change 60cmHg to pascal​
xenn [34]

Answer:

1cmhg= 1333.22pa

60cmhg= 60×1333.22

60cmhg=79993.2pa

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3 years ago
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