Answer: have a subject and a verb
Explanation:
The units that are used to measure mass are grams. The units that are used to measure weight are pounds and ounces.
Answer:
![v = 4.7 m/s](https://tex.z-dn.net/?f=v%20%3D%204.7%20m%2Fs)
Explanation:
As we know that the ball is swinging in a circle
so here net horizontal centripetal force on the ball is due to component of the tension force
so we will have
![T sin\theta = m\omega^2 r](https://tex.z-dn.net/?f=T%20sin%5Ctheta%20%3D%20m%5Comega%5E2%20r)
![T cos\theta = mg](https://tex.z-dn.net/?f=T%20cos%5Ctheta%20%3D%20mg)
also we know that
![T = Mg](https://tex.z-dn.net/?f=T%20%3D%20Mg)
so we have
![Mg cos\theta = mg](https://tex.z-dn.net/?f=Mg%20cos%5Ctheta%20%3D%20mg)
![\theta = \frac{1}{2}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![\theta = 60 degree](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2060%20degree)
now we have
![Mg sin\theta = m\omega^2 (Lsin\theta)](https://tex.z-dn.net/?f=Mg%20sin%5Ctheta%20%3D%20m%5Comega%5E2%20%28Lsin%5Ctheta%29)
![Mg = m\omega^2 L](https://tex.z-dn.net/?f=Mg%20%3D%20m%5Comega%5E2%20L)
![2 \times 9.81 = 1 \omega^2 (1.5)](https://tex.z-dn.net/?f=2%20%5Ctimes%209.81%20%3D%201%20%5Comega%5E2%20%281.5%29)
![\omega = 3.62 rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%203.62%20rad%2Fs)
now we have
![v = r\omega](https://tex.z-dn.net/?f=v%20%3D%20r%5Comega)
![v = (1.5 sin60) (3.62)](https://tex.z-dn.net/?f=v%20%3D%20%281.5%20sin60%29%20%283.62%29)
![v = 4.7 m/s](https://tex.z-dn.net/?f=v%20%3D%204.7%20m%2Fs)
<h2>
Mass of object in Earth is 1.37 kg</h2>
Explanation:
On planet B where the magnitude of the free-fall acceleration is 1.91g , the object weighs 25.74 N.
We have
Weight = Mass x Acceleration due to gravity
On planet B
25.74 = Mass x 1.91 g
25.74 = Mass x 1.91 x 9.81
Mass = 1.37 kg
Mass is constant for an object. It will not change with location.
Mass of object in Earth = Mass of object in Planet B
Mass of object in Earth = 1.37 kg