Answer:
the correct answer is C, 281 lb
Explanation:
This is an exercise in fluid mechanics specifically on Pascal's principle, which states that the pressure in a fluid is equal to all points that are at the same depth
P =
= 
If we use the subscript 1 for the piston diameter mentor (d = 1.00vm) which is r = 0.05 cm, the force is F1 = 45 lb
F₂ = \frac{F_{1} }{A_{1} } F₁
in area of a circules
A = π r²
we substitute
F₂ =
let's calculate
F2 = 2.50² / 1.00² 45
F2 =281 lb
therefore the correct answer is C
The collision of the two waves would bring force and that would make the new wave smaller
Answer:
The work done on the gas = 2PV
Explanation:
In this question, we need to apply the basic gas laws to determine the word done.
For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.
So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.
As we know that, the work done on the gas is equal to the area under the curve.
W = Area of the triangle
W = 0.5 x ( base) x ( height)
W = 0.5 x (BC) x (AC)
W = 0.5 x (3V-V) x (3P-P)
W = 2PV
Hence, the work done on the gas = 2PV
Answer:

°
Explanation:
Let's use the component method of vector addition:

Now, we know:

So:

Now lets calculate the magnitude of the vector B:

Finally its angle is given by:
°
Keep in mind that I added 180 to the angles of C and B to find the real angles measured from the + x axis counter-clock wise.
Newton's third law: For every action, there is an opposite and equal reaction.