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sergeinik [125]
3 years ago
6

Can I have help please? i need it!

Physics
1 answer:
EastWind [94]3 years ago
4 0
The answer is a hope this helps 
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If your body has a density of 955 kg/m3, what fraction of you will be submerged when floating gently in:
wel

Answer: (a) 99.5℅ submerged

(B) 96.9℅ submerged

Explanation:

For 995 kilograms per cubic meter, It'll be the 995Kg/m3 density given, divided by the density of fresh water, which is one times ten to the three kilograms per cubic meter, and this works out to 99.5 percent submerged.

If the same person with the same density was floating in salt water, salt water has a slightly higher density of 1027 kilograms per cubic meter, this works out to 96.9 percent submerged.

6 0
4 years ago
Your friend says that for a moving object to continue moving, a force must be continually applied to it. Do you agree with your
Zigmanuir [339]

Answer:

I would disagree with my friend because that according to Newton's first law, an object in motion will continue to be in motion until stopped by another object/force. If the object is already moving, it will stay in motion until something else stops it. There is no need for a force to be <em>continually</em> applied to it while it's already moving.

4 0
2 years ago
A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A bloc
Nikitich [7]

Answer:

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

Explanation:

From the law of conservation of energy

Energy lost  by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr

0.5kd^{2}=0.5mv^{2}+mgLsin\theta+\mu_{k}mgcos\theta x

x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

The required distance from A to B is x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

5 0
3 years ago
Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distan
aivan3 [116]

Answer:

The fringes are 4.7*10^-7 m apart, such that they are adjacent.

Explanation:

Using the formula for adjacent fringes given a single slit:

Δx=\frac{(Wavelength)(Distance between slit and screen)}{Width}

Δx=\frac{(590/10^{9})(1.90) }{(2.30)}

Δx=0.000000487 m

Hope this helps!

7 0
2 years ago
Read 2 more answers
CAN ANYONE HELP PLEASE I NEED THIS DONE BY TODAY!! I WILL MARK YOU BRIANLYIST.
bulgar [2K]
I have no idea my dude sorry
7 0
3 years ago
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