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3 years ago

6

What is the solar panel of a plant cell? A. Chloroleon B. Chlorodrop C. Chloroplast D. Chlorohydrates

2 answers:

myrzilka [38]3 years ago

6 0

The solar panel of a plant cell is the CHLOROPLAST

Mariana [72]3 years ago

4 0

It is obviously the chloroplast, since it absorbs all the light

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What is the covalent bond for Hydrogen + Chlorine (HCI)

kolbaska11 [484]

Answer:

HCl, also known as hydrochloric acid, has a covalent bond. The hydrogen (H) atom shares an electron with the chlorine (Cl) to form the bond.

Explanation:

Consequently, the bonding electrons in hydrogen chloride are shared unequally in a polar covalent bond. The molecule is represented by the conventional Lewis structure, even though the shared electron pair is associated to a larger extent with chlorine than with hydrogen.

6 0

3 years ago

The first step in industrial nitric acid production is the catalyzed oxidation of ammonia. Without a catalyst, a different react

murzikaleks [220]

<u>Answer:</u> The value of $K_{eq}$ is $4.84\times 10^{-5}$

<u>Explanation:</u>

We are given:

Initial moles of ammonia = 0.0280 moles

Initial moles of oxygen gas = 0.0120 moles

Volume of the container = 1.00 L

Concentration of a substance is calculated by:

$\text{Concentration}=\frac{\text{Number of moles}}{\text{Volume}}$

So, concentration of ammonia = $\frac{0.0280}{1.00}=0.0280M$

Concentration of oxygen gas = $\frac{0.0120}{1.00}=0.0120M$

The given chemical equation follows:

$4NH_3(g)+3O_2(g)\rightleftharpoons 2N_2(g)+6H_2O(g)$

<u>Initial:</u> 0.0280 0.0120

<u>At eqllm:</u> 0.0280-4x 0.0120-3x 2x 6x

We are given:

Equilibrium concentration of nitrogen gas = $3.00\times 10^{-3}M=0.003$

Evaluating the value of 'x', we get:

$\Rightarrow 2x=0.003\\\\\Rightarrow x=0.0015M$

Now, equilibrium concentration of ammonia = $0.0280-4x=[0.0280-(4\times 0.0015)]=0.022M$

Equilibrium concentration of oxygen gas = $0.0120-3x=[0.0120-(3\times 0.0015)]=0.0075M$

Equilibrium concentration of water = $6x=(6\times 0.0015)]=0.009M$

The expression of $K_{eq}$ for the above reaction follows:

$K_{eq}=\frac{[H_2O]^6\times [N_2]^2}{[NH_3]^4\times [O_2]^3}$

Putting values in above expression, we get:

$K_{eq}=\frac{(0.009)^6\times (0.003)^2}{(0.022)^4\times (0.0075)^3}\\\\K_{eq}=4.84\times 10^{-5}$

Hence, the value of $K_{eq}$ is $4.84\times 10^{-5}$

4 0

3 years ago

Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000

olga55 [171]

The answer is D! 512000000

5 0

3 years ago

Read 2 more answers

Consider the reaction 2CuCl2 + 4K - 2Cul + 4KCI + 12. If 4 moles of CuCl2 react with 4 moles of KI, what is the limiting reactan

Free_Kalibri [48]

Haha i’m trying to do the same one i’ll make sure if i find out how too to get back to you!

8 0

3 years ago

How many moles of nacl are required to make 500. 0 ml of a 0. 1 m solution of nacl?.

Illusion [34]

Answer:

Therefore 500 ml of solution have 0.25 mol of NaCl .. = 14.61 g (ans.)

Explanation:

7 0

2 years ago