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svet-max [94.6K]
3 years ago
13

how much thermal energy is absorbed by a copper water pipe with a mass of 2.3kg when its temperature is raised from 20.0 to 80.0

?
Physics
1 answer:
Sphinxa [80]3 years ago
3 0

Explanation:

q = mCΔt

q = (2.3 kg) (385 J/kg/K) (80.0°C − 20.0°C)

q ≈ 53,000 J

q ≈ 53 kJ

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Increase in sea water pollution
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The flow of electricity can be compared of water in
Anna007 [38]

The flow of electricity can be compared of water in the pipes because both water and electricity moves in the channel.

<h3>How we compare the flow of electricity to water?</h3>

Water flowing in pipes is like flowing of electricity in a circuit. A battery is like a pump from where electricity comes and moves in the circuit. Electrons flowing through wires are like water molecules flowing through pipes. So in comparison between water and electricity, both water and electricity are similar to each other in flowing and movement.

So we can conclude that the flow of electricity can be compared of water in the pipes because both water and electricity moves in the channel.

Learn more about electricity here: brainly.com/question/776932

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7 0
2 years ago
the frequency of the middle b note on a piano is 493.88 hz. what is the wavelength of this note in centimeters? the speed of sou
vekshin1

Answer:

69.5

Explanation:

V=FX

343.06=493.88×X

X=343.06/493.88

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5 0
3 years ago
What is the energy in space left over from the big bang called
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It is called the CMBR, which stands for cosmic microwave background radiation. It was discovered by Arno Penzias and Robert Wilson in 1964.
5 0
3 years ago
A 12.0-cm long cylindrical rod has a uniform cross-sectional area A = 5.00 cm2. However, its density increases linearly from 2.6
andriy [413]

Answer:

(a) The constants required describing the rod's density are B=2.6 and C=1.325.

(b) The mass of the road can be found using A\int_0^{12}\left(B+Cx)dx

Explanation:

(a) Since the density variation is linear and the coordinate x begins at the low-density end of the rod, we have a density given by

2.6\frac{g}{cm^3}+\frac{18.5\frac{g}{cm^3}-2.6\frac{g}{cm^3}}{12 cm}x = 2.6\frac{g}{cm^3}+1.325x\frac{g}{cm^2}

recalling that the coordinate x is measured in centimeters.

(b) The mass of the rod can be found by having into account the density, which is x-dependent, and the volume differential for the rod:

m=\int\rho dv=\int\left(B+Cx\right)Adx=5\int_0^{12}\left(2.6+1.325x\right)dx=126.6,

hence, the mass of the rod is 126.6 g.

7 0
3 years ago
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