Steam enters a well-insulated turbine operating at steady state at 4 MPa with a specific enthalpy of 3015.4 kJ/kg and a velocity
of 10 m/s. The steam expands to the turbine exit where the pressure is 0.07 MPa, specific enthalpy is 2500 kJ/kg, and the velocity is 90 m/s. The mass flow rate is 17 kg/s.
A) Neglecting potential energy effects, determine the power developed by the turbine, in kW.
A) Neglecting potential energy effects, determine the power developed by the turbine, in kW.
1 answer:
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Answer:
13.) 44V
14.) 66V
15.) 9A
16.) 12V
Explanation:
Concepts you need to know:
1. Resistors in series can be combined by summing up their values.
2. The current always stays the same when the resistors are in series.
3. Ohms Law:
13.) We know that the resistors are in series so we can combine them into a single big resistor. We got R₄ = R₃+R₂+R₁ = 2+4+5 = 11Ω.
We also know that current is the same in a series of resistors, so there's 4A going through the entire circuit.
Using ohm's law, we can calculate V = IR = (4)(11) = 44V
14.) Same explanation as part (13). Except now the current is I=6A. All we have to do is to replace the previous I=4 to I=6.
V = IR = (6)(11) = 66V
15.) Again, we know that current is the same when resistors are in series. So if you can find the current through R1 then that's the same current throughout the entire circuit.
We're given E₁=18V, so...
I = V/R = E₁/R₁ = 18/2 = 9A
this means 9A will also flow through R₃.
16.) Same concept as part (15). We know that E₃=15V, so lets find the current.
I = V/R = E₃/R₃ = 15/5 = 3A
Since current is same throughout the circuit, I₁=3A as well. Use this to calculate the voltage through R₁.
V = IR = I₁R₁ = (3)(2) = 6V
We can find the change in the enthalpy through the tables A5 for Saturated water, pressure table.
For 1bar=1000kPa:
Replacing,
With the specific volume we know can calculate the mass flow, that is
Then the heat required in input is,
With the same value required of 15000m^3/h, we can calculate the velocity of the water, that is given by,
Finally we can apply the steady flow energy equation, that is
Re-arrange for Q,
We can note that consider the Kinetic Energy will decrease the heat input.
Answer:
import java.util.Scanner;
import java.io.*;
public class Main{
public static void main(String []args){
StringBuilder reversedName = new StringBuilder();
StringBuilder subName = new StringBuilder();
Scanner myObj = new Scanner(System.in); // Create a Scanner object
System.out.println("Enter your full name (last name + first name)");
String name = myObj.nextLine(); // Read user input
for (int i = 0; i < name.length(); i++) {
char currentChar = name.charAt(i);
if (currentChar != ' ') {
subName.append(currentChar);
} else {
reversedName.insert(0, currentChar + subName.toString());
subName.setLength(0);
}
}
String Resul = reversedName.insert(0, subName.toString()).toString();
System.out.println("Reverse full name: " + Resul);
}
}
Explanation:
To solve the problem we used StringBuilder, that allow us to build a string letter by letter, we are using two, one to store temporary information (subName) and the other to store the surname plus name (reversedName). After defining the variables, the program asks for the user fullname using Scanner class and it's method .nextLine (the variable 'name' will save the user input). A while loop is also used to iterate over the name, taking character by character with the method .charAt, the program will append letters in subName until it finds a space only then the content of subName will be transfer to reversedName and the content of subName will be deleted, then the program continues with the process until the end of the for loop; finally, the program places the content of subName at the beginning of reversedName, and print the result transforming the StringBuilder to a normal string.
