The motion of a falling whirligig is different to that of a falling paper ball due to spinning.
<h3>Type of motion performed by whirligig and falling paper ball </h3>
The motion of a falling whirligig is different from the motion of a falling paper ball because the paper ball falls on the ground without spinning while on the other hand, the whirligig falls on the ground along with spinning.
The falling whirligig performs two motion i.e. one is falling on the ground and the other is spinning during motion whereas paper ball performs one motion i.e. motion in the air towards the ground so we can conclude that the motion of a falling whirligig is different than of a falling paper ball.
Learn more about motion here: brainly.com/question/453639
The potential energy that the ball has at the top of the tower is its kinetic energy when it hits the ground. The second ball has more potential energy at the top, because you did more work on it to carry it up there. So it has more KE at the bottom. (A)
Answer:
-The speed of sound at 33°C is 362.8 m/s.
-The wavelength at a frequency at 5 kHz is 0.07256 m .
Explanation:
let v = 343 m/s be the speed of sound.
let T be the temperature.
then the speed of sound V, at 33°C is given by:
V = v + 0.6×T
= 343 + 0.6×33
= 362.8 m/s
Therefore, the speed of sound at 33°C is 362.8 m/s.
the wavelength at a frequency of f = 5kHz = 5000 Hz is given by:
λ = V/f
= (362.8)/(5000)
= 0.07256 m
Therefore, the wavelength at a frequency at 5 kHz is 0.07256 m .
<span>Answer:
Therefore, x component: Tcos(24°) - f = 0 y component: N + Tsin(24°) - mg = 0 The two equations I get from this are: f = Tcos(24°) N = mg - Tsin(24°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24°) = 0.47 * (mg - Tsin(24°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24°) + sin(24°) * static coefficient) Then plugging in the values... T = 283.52.
Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/</span>
