1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
san4es73 [151]
3 years ago
12

Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation

of two new nuclei and neutrons. The following equation is an example of one such fission process: 235 92U+10n→AZBa+9436Kr+310n
Enter the isotope symbol for the barium (Ba) nucleus in this reaction.In another process in which 235 92U undergoes neutron bombardment, the following reaction occurs:235 92U+10n --> AZSr+143 54Xe+310nEnter the isotope symbol for the strontium (Sr) nucleus in this reaction.
Chemistry
1 answer:
nikdorinn [45]3 years ago
7 0

<u>Answer:</u> The isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

<u>Explanation:</u>

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is _{56}^{139}\textrm{Ba}

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is _{38}^{89}\textrm{Sr}

Hence, the isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

You might be interested in
How many moles are in 9.12 x 1023 molecules of sugar?​
aleksandrvk [35]

Answer:

1.514 moles

Explanation:

For this problem you want to use dimensional analysis and cancel out your molecules of sugar and be left with moles of sugar. We know that 1 mole (of anything) = 6.022 x 10 ^ 23 molecules, so we should use that conversion to help us. Start with 9.12 x 10 ^23 molecules and divide by 6.022 x 10 ^ 23 molecules, and you will be left with moles.

Hope this helps!

3 0
2 years ago
Why can't methanol, CH3OH, be used as a solvent for sodium amide, NaNH2? Sodium amide is nonpolar and methanol is polar. Sodium
Elodia [21]

Answer: sodium amide undergoes an acid -base reaction

Explanation:

sodium amide is a ionic compound and basically exists as sodium cation and amide anion. Amide anion is highly basic in nature and hence as soon as  there is amide anion generated in the solution , Due to its very pronounced acidity it very quickly abstracts the slightly acidic proton available on methanol.

This leads to formation of ammonia and sodium methoxide.

Hence sodium amide reacts with methanol and abstracts its only acidic proton and form ammonia and sodium Methoxide.

Hence the 3rd statement is a corrects statement.

So we cannot use methanol for sodium amide because sodium amide itself would react with methanol and the inherent molecular natur of sodium amide would then change.

The 1st and 2nd statements both are incorrect because both the compounds methanol as well as sodium amide have dipole moments and hence are polar molecules.

The 4th statement is also incorrect as both the molecules have dipole moment and hence there would be ion-dipole forces operating between them.

The following reaction occurs:

NaNH₂+CH₃OH→NH₃+CH₃ONa

4 0
3 years ago
Lewis dot structure for N3-
labwork [276]

Answer :

The steps involved in the electron dot structure of N^{3-} are :

First we have to determine the total number of valence electron in N^{3-}.

Number of valence electrons in N = 5

The charge on N is (-3). So, we add 3 electrons.

Total number of valence electrons = 5 + 3 = 8 electrons

The image is shown below.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME I BEG PLEASE!!!!
cricket20 [7]
1.Decomposition i think
2.boiling
3.It is a solid at room temperature and pressure.
4.<span>The base donates a hydrogen ion.
5.That causes the oxidation of another element
6.</span>MnO2
7.When a substance is reduced, electrons are lost.
8.True I think
9.False
10.True

Hope these are correct
3 0
3 years ago
Read 2 more answers
Rank the following compounds in order of decreasing acid strength using periodic trends.Rank the acids from strongest to weakest
Naddika [18.5K]

HBr>H2S>H2Se>BH3 so basically

1. HBr

2. H2S

3. H2Se

4. BH3

4 0
3 years ago
Read 2 more answers
Other questions:
  • Draw the kinetic and thermodynamic enolates formed when 3-methylbutan-2-one (methyl isopropyl ketone) is treated with base. Incl
    8·1 answer
  • Your sense of touch is based in your _____.<br> bones<br> muscles<br> skin<br> tissues
    13·1 answer
  • Molar mass of (NaOH)
    15·1 answer
  • The difference between the formula you just wrote out and the molecular formula of compound E is one atom. That atom is part of
    8·1 answer
  • I need these questions answered
    5·2 answers
  • 13. big one , sorry if it is a lot , but I really need help
    6·1 answer
  • Scientists often look at how much isotopes of ______
    11·1 answer
  • 33. A basketball bounces on the gym floor nine times and finally comes to a rest. Which of these BEST explains why the
    10·1 answer
  • Using g= 10 m/s?, find the weight of a 3 kg mass.
    5·1 answer
  • Select the correct answer.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!