Answer:
0.22 m
Explanation:
= Atmospheric pressure = 101325 Pa
= Pressure at the bottom = tex]2 P_{o}[/tex] = 2 (101325) = 202650 Pa
= height of the container = 7.59 m
= depth of the mercury
Pressure at the bottom = Atmospheric pressure + Pressure due to mercury + Pressure due to water
Answer:
5.44×10⁶ m
Explanation:
For a satellite with period t and orbital radius r, the velocity is:
v = 2πr/t
So the centripetal acceleration is:
a = v² / r
a = (2πr/t)² / r
a = (2π/t)² r
This is equal to the acceleration due to gravity at that elevation:
g = MG / r²
(2π/t)² r = MG / r²
M = (2π/t)² r³ / G
At the surface of the planet, the acceleration due to gravity is:
g = MG / R²
Substituting our expression for the mass of the planet M:
g = [(2π/t)² r³ / G] G / R²
g = (2π/t)² r³ / R²
R² = (2π/t)² r³ / g
R = (2π/t) √(r³ / g)
Given that t = 1.30 h = 4680 s, r = 7.90×10⁶ m, and g = 30.0 m/s²:
R = (2π / 4680 s) √((7.90×10⁶ m)³ / 30.0 m/s²)
R = 5.44×10⁶ m
Notice we didn't need to know the mass of the satellite.
Answer:
12.5 m.
Explanation:
Speed: This can be defined as the rate of change of distance. The S.I unit of speed is m/s. Mathematically it can be expressed as,
Speed = distance/time
S = d/t......................... Equation 1
d = S×t ...................... Equation 2.
Where S = speed of the car, d = distance, t = time taken to shut the eye during sneezing
Given: S = 90 km/h, t = 0.50 s.
Conversion: 90 km/h ⇒ m/s = 90(1000/3600) = 25 m/s.
S = 25 m/s.
Substitute into equation 2.
d = 25×0.50
d = 12.5 m.
Hence the car will move 12.5 m during that time
Answer: Light is a form of electromagnetic radiation because it has the ability to travel from one type of medium to another and can also carry some energy along with it. A light wave has two components, namely the electric field component as well as the magnetic field component that are both perpendicular to the propagating direction.
The visible light lies between the ultraviolet and the infrared lights, with wavelength from 400 nm to 700 nm respectively. This is collectively known as the visible spectrum of light.
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