All categories

3 years ago

Ions that are made of more than one atom are examples of

2 answers:

8 0

These ions are polyatomic ions. The prefix "poly-" means "many," and the rest of the word "atomic" clearly refers to the atoms themselves. So, if there are two or more atoms in an ion, this ion is polyatomic.

Ket [755]3 years ago

6 0

Letter A is your answer

You might be interested in

A 0.187 M weak acid solution has a pH of 3.99. Find Ka for the acid. Express your answer using two significant figures.

Anna35 [415]

Answer:

5.56 × 10⁻⁸

Explanation:

Step 1: Given data

Concentration of the weak acid (Ca): 0.187 M

pH of the solution: 3.99

Step 2: Calculate the concentration of H⁺

We will use the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -3.99 = 1.02 × 10⁻⁴ M

Step 3: Calculate the acid dissociation constant (Ka)

We will use the following expression.

$Ka = \frac{[H^{+}]^{2} }{Ca} = \frac{(1.02 \times 10^{-4})^{2} }{0.187} = 5.56 \times 10^{-8}$

3 0

3 years ago

SeF6 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs

Anarel [89]

The answer is- $SF_{6}$ is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of $SF_{6}$ .

Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
Now, calculate the total number of valence electrons in $SF_{6}$ .

$Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)$

Valence electrons of S = 6

Valence electrons of F = 7

Thus, the valence electrons in $SF_{6}$ are-

$Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.$

The Lewis structure of $SF_{6}$ is - (Image attached).
In the structure, the number of atoms bonded to central atom (S) = 6.
Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
Electronic geometry in case of 6 bond pairs is octahedral.
Molecular geometry us also octahedral with bond angles 90°.
Central atom is sp3d2 hybridised.
$SF_{6}$ is a non-polar molecule.

To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

#SPJ4

7 0

1 year ago

When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e

sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

2 Al(s) + 3Cl₂(g) ⇒ 2AlCl₃

Process

a) Calculate the molar mass of the reactants

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion Al/Cl₂ = 53.96/212.7 = 0.254

Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

53.96 g of Al ------------------ 212.7 g of Cl₂

40.5 g of Al ------------------- x

x = (40.5 x 212.7) / 53.96

x = 8614.35 / 53.96

x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

= 53.057 g

d) Calculate the moles of Cl

35.45 g of Cl ----------------- 1 mol

53.057 g of Cl --------------- x

x = (53.057 x 1)/35.45

x = 1.49 mol of Cl₂

6 0

3 years ago

Read 2 more answers

Hydrogen and nitrogen react to produce ammonia gas as shown in the following chemical

DerKrebs [107]

Explanation:

$31.5 \: g \: aommnia \: \times \: \frac{1 \: mol \: ammonia}{8 \: g \: ammonia \: } \: \times \frac{3 \: mol \: hydrogen}{2 \: mol \: ammonia} \: \times \frac{1 \: g \: hydrogen}{1 \: mol \: hydrogen} = \: 5.90625 \: g \: hydrogen \: must \: react \:$

5 0

3 years ago

5. Acid + Metal → a Salt + _______

aliya0001 [1]

The answer is Hydrogen

This is what happens when acids react with metals

5 0

3 years ago

Read 2 more answers