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Veseljchak [2.6K]
2 years ago
9

If an oxygen nucleus consists of eight protons and eight neutrons, the charge on that nucleus is positive. Since even I learned

in high school that like charges repel, such a nucleus would find all its positive protons repelling and quickly fall apart." How would you answer his argument?
Chemistry
1 answer:
Delvig [45]2 years ago
4 0

Answer:

The binding energy present in the atomic nucleus that holds the protons and the neutrons together and its magnitude is one million times stronger than the electron binding energy in small atoms

Explanation:

The minimum required force to dismember an atomic nucleus into its constituent components, of protons and nucleus (collectively called nucleons) in known as the nuclear binding energy.

Energy is required in separating the nucleons hence the binding energy of a nucleus is always positive

According to Einstein's Energy and light relation E = mc², when a nucleus is formed from the number of free protons and neutrons, the sum of their individual masses is more than the mass of the formed atomic nucleus. The mass deficit of the neutron, also known as the 'missing mass' or mass defect indicates the amount of energy released in forming of the nucleus which therefore has different characteristics from its constituents as mentioned above

The amount of mass that is equivalent to the binding energy of the nucleus as shown in the Einstein's equation (E=mc²) is represented by the missing mass or mass defect of the formed nucleus or the difference in mass between the nuclear mass and that of the sum of the individual masses of its constituent protons and neutrons

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The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh
Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

150.0 mL \times \frac{1.02g}{mL}  = 153 g

Given the specific heat capacity of the solution (c) is 4.184 J/g・°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J  }{\frac{4.184J}{g.\° C }  \times 153g} = 5.87 \° C

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

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