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Alex Ar [27]
4 years ago
13

if two waves with equal amplitudes and wavelengths travel through a medium in such a way that a particular particle of the mediu

m is at the crest of one wave and at the trough of the other wave at the same time, what will happen to that particle?
Physics
2 answers:
Novosadov [1.4K]4 years ago
8 0
If two waves with equal amplitude and wavelength travel through a medium such that particular particle is at the crest of one wave and at the trough of another wave, then destructive interference will take place.Both waves will cancel each other out at that point such that a node will form in which the particle will remain at its rest position only and will not move. 
Irina-Kira [14]4 years ago
8 0

Answer:

As per the law of superposition we know that when two waves superimpose at a point on the medium then the resultant displacement of the medium particle is vector sum of the displacement due to each wave.

So here by superposition principle we can write

y_{net} = y_1 + y_2

now here we know that one of the wave reaches with crest while other wave reaches at trough position.

So we will have

y_1 = +A

y_2 = -A

so here by superposition we will have

y_{net} = A - A = 0

so after superposition the medium particle will come to its mean position.

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Find the speed required to throw a ball straight up and it return 6 seconds later. Neglect air resistance
Nadya [2.5K]

Answer:

the ball will go up 3s and down 3s

v=gt

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Explanation:

8 0
3 years ago
What is a car’s acceleration if it increases its speed from 5 m/s to 20 m/s in 3 s? 10 m/s2 –15 m/s2 15 m/s2 5 m/s2
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5 m/s²

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6 0
2 years ago
The smallest angle of inclined desk at which a book begins to slide off the desk is 15∘ relative to the horizontal.
Ray Of Light [21]
The question appears to be incomplete.
I assume that we are to find the coefficient of static friction, μ, between the desk and the book.

Refer to the diagram shown below.
m = the mass of the book
mg = the weight of the book (g = acceleration due to gravity)

N = the normal reaction, which is equal to
N = mg cos(12°)

R =  the frictional force that opposes the sliding down of the book. It is
R = μN = μmg cos(12°)

F =  the component of the weight acting down the incline. It is
F = mg sin(12°)

Because the book is in static equilibrium (by not sliding down the plane), therefore
F = R
mg sin(12°) = μmg cos(12°)
\frac{sin(12^{o})}{cos(12^{o})} =  \frac{\mu mg}{mg} = \mu \\\\
tan(12^{o}) = \mu

Therefore, the static coefficient of friction is
μ = tan(12) = 0.213

Answer:  μ = 0.21 (nearest tenth)

6 0
3 years ago
Read 2 more answers
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