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Alex Ar [27]
4 years ago
13

if two waves with equal amplitudes and wavelengths travel through a medium in such a way that a particular particle of the mediu

m is at the crest of one wave and at the trough of the other wave at the same time, what will happen to that particle?
Physics
2 answers:
Novosadov [1.4K]4 years ago
8 0
If two waves with equal amplitude and wavelength travel through a medium such that particular particle is at the crest of one wave and at the trough of another wave, then destructive interference will take place.Both waves will cancel each other out at that point such that a node will form in which the particle will remain at its rest position only and will not move. 
Irina-Kira [14]4 years ago
8 0

Answer:

As per the law of superposition we know that when two waves superimpose at a point on the medium then the resultant displacement of the medium particle is vector sum of the displacement due to each wave.

So here by superposition principle we can write

y_{net} = y_1 + y_2

now here we know that one of the wave reaches with crest while other wave reaches at trough position.

So we will have

y_1 = +A

y_2 = -A

so here by superposition we will have

y_{net} = A - A = 0

so after superposition the medium particle will come to its mean position.

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iragen [17]
You’re correct, it’s gravity
5 0
3 years ago
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On dry concrete, a car can decelerate at a rate of 7.00 m/s2 , whereas on wet concrete it can decelerate at only 5.00 m/s2 . Fin
MariettaO [177]

Answer:

Explanation:

a ) Let the distance required in former case be d₁ .

initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 7.00 m /s²

v² = u² - 2 a s

0 = 30² - 2 x 7 x d₁

d₁ = 64.28 m

b) initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 5.00 m /s²

v² = u² - 2 a s

0 = 30² - 2 x 5 x d₂

d₂ = 90  m

c)

t = .5 s

s₁  = ut - .5 at²

= 30 x .5 - .5 x 7 x .5²

= 15 - .875

= 14.125 m

t = .5 s

s₂  = ut - .5 at²

= 30 x .5 - .5 x 5 x .5²

= 15 - .625

= 14.375  m

3 0
4 years ago
You find a measurement or 34 kg written in a laboratory notebook. What physical characteristic is this a measurement of?
Elis [28]
Planck's constant. A physical constant adopted in 2011 by the CGPM.
7 0
4 years ago
An airplane is traveling at a fixed altitude with an outside wind factor. The airplane is headed N 40° W at a speed of 600 miles
bija089 [108]

Answer:\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

Explanation:

Given

Plane is initially flying with velocity of magnitude v=600\ mph

at angle of 40^{\circ} with North towards west

Velocity of plane airplane can be written as

v_a=600(-\sin 40\hat{i}+\cos 40\hat{j})

Now wind is encountered with speed of v=80\ mph at angle of N45^{\circ}E

v_w=80(\cos 45\hat{i}+\sin 45\hat{j})

resultant velocity

\vec{v_R}=\vec{v_a} +\vec{v_w}

\vec{v_R}=600(-\sin 40\hat{i}+\cos 40\hat{j})+ 80(\cos 45\hat{i}+\sin 45\hat{j})

\vec{v_R}=\hat{i}[-385.67+56.56]+\hat{j}[459.62+56.56]

\vec{v_R}=\hat{i}[-329.11]+\hat{j}[516.18]

for direction \tan \theta =\frac{516.18}{329.11}

\tan \theta =1.568

\theta =57.47^{\circ} west of North

3 0
4 years ago
Hire rubs an inflated balloon on his hair and his hair sticks to the balloon as he moves the balloon away from his head how does
sergey [27]

The options are missing and they are;

A) the electric force increases because the balloon loses its charge.

B) the electric force increases because the distance increases.

C) the electric force decreases because the distance increases.

D) the electric force decreases because his hair loses its charge.

Answer:

Correct answer is option C - the electric force decreases because the distance increases.

Explanation:

The formula for electric force is;

F = k•q1•q2/r²

Where;

K is coulombs constant

q1 and q2 are particle charges

r is distance

So,looking at the formula given earlier, if we increase the distance, the denominator will increase and thus the Force will decrease.

So the correct option is option C

8 0
3 years ago
Read 2 more answers
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