The relationship between the pitcher plant and the insects is an example of (competition/predation/symbiosis).

2 answers:

8 0

A team of students believe that a decline in the number of sea urchins will affect the organisms in the kelp forest ecosystem

Tresset [83]3 years ago

4 0

Predation, because the pitcher plant is preying on the insects.

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What method of separation would work best on a homogeneous mixture salt water? Select all that apply. filtration distillation ev

yuradex [85]

Evaporation because the salt would dissolve in the water then boil the water and it will evaporate leaving the salt left in the bowl

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3 years ago

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What is the molarity of a solution if 300.0 ml of it contains 16.8 g of kno3? [formula weight: kno3, 101.11 amu]?

AVprozaik [17]

The molarity is count by dividing the mole of the solute within 1 liter of solvent. In this case, the KNO3 is 16.8g with 101.11 g/mol molar mass. Then we need to find the mol first. The calculation would be: 16.8g / (101.11g/mol)= 0.0166 mol.

Then the molarity would be: 0.0166mol/ 0.3l= 0.0498= 0.0553 M

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3 years ago

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Rust forming on a piece of iron is an example of which of the following? *

kvasek [131]

Rust is an iron oxide and formed by the reaction of iron and oxygen in the presence of moisture. So the answer would be C

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3 years ago

What is the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65% oxygen?

aliya0001 [1]

Li2CO3 ; variance= 1.26x10^-3

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3 years ago

GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g

JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

$H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ$

Divide the equation by 2.

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

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3 years ago