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Marianna [84]
2 years ago
5

Solve the following system of linear equations. 3x + 2y = 10 2x + 3y = 15/2 No solution y = (-3/2)x + 5 x = 3, y = -1/2 x = 3, y

= 1/2
Mathematics
1 answer:
frutty [35]2 years ago
5 0
3x + 2y = 10 .....multiply by -2
2x + 3y = 15/2...multiply by 3
------------------
-6x - 4y = -20 (result of multiplying by -2)
6x + 9y = 22.5 (result of multiplying by 3)
-----------------add
5y = 2.5
y = 2.5/5
y = 1/2

3x + 2y = 10
3x + 2(1/2) = 10
3x + 1 = 10
3x = 10 - 1
3x = 9
x = 9/3
x = 3

solution is (3,-1/2)
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Answer:

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Step-by-step explanation:

+ Because of "the line passing through the pair of points (2,3) and (5,9)", that means the line has the equation y = ax + b where a = (9-3)/(5-2)= 6/3= 2

+ So the equation is y = 2x + b.

+ Then we replace x= 2 and y= 3 into y = 2x + b for finding  like:

3 = 2*2 + b or 3 = 4 + b, so we find b = 3 - 4 = - 1.

+ The equation of this line is y = 2x - 1 or in the form:

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3 years ago
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Read 2 more answers
2x-5) = 2(x-5) One Solution Infinitely Many Solutions No Solution 5x + 4) = 5(1-6) 5(x + 4) = 3(x-6) 4x - 2) = 4(x + 2) x + 2(x-
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9514 1404 393

Answer:

  top down: ∞, 0, 1, 0, ∞

Step-by-step explanation:

The equation will have infinite solutions when the left side and right side simplify to the same expression. This is the case for the first and last expressions listed.

  2(x -5) = 2(x -5) . . . . expressions are already identical

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__

The equation will have no solutions when the x-coefficients are the same, but there are different added constants.

  5(x +4) = 5(x -6)  ⇒  x +4 = x -6  . . .  not true for any x

  4(x -2) = 4(x +2)  ⇒  x -2 = x +2  . . .  not true for any x

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The equation will have one solution when coefficients of x are different.

  5(x +4) = 3(x -6)  ⇒  2x = -38  ⇒ x = -19

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Step-by-step explanation:

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