Consider the motion towards right as positive and motion towards left as negative.
m₁ = mass of the cart moving to right = 0.500 kg
v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s
m₂ = mass of cart moving to left = 0.800 kg
v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s
initial momentum of the system of carts before the collision is given as
P₁ = m₁ v₁ + m₂ v₂
P₁ = (0.500) (2.2) + (0.800) (- 1.1)
P₁ = 0.22 kg m/s
P₂ = momentum of system of carts after collision
As per conservation of momentum,
Momentum of system of carts after collision = Momentum of system of carts before collision
P₂ = P₁
P₂ = 0.22 kg m/s
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
<h3>For smaller balloon:</h3>
- Radius (r) = 3 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 3³
<h3>V = 113.04 cm³</h3>
<h3>For larger balloon:</h3>
- Radius (r) = 6 cm
- Pi (π) = 3.14
- Volume (V) =?
V = 4/3 πr³
V = 4/3 × 3.14 × 6³
<h3>V = 904.32 cm³</h3>
Finally, we shall determine how much greater the larger balloon is to the smaller balloon
- Volume of smaller balloon = 113.04 cm³
- Volume of larger balloon = 904.32 cm³
- Greatness =?
Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
<h3>Large = 8 × small </h3>
Therefore, the larger balloon is 8 times greater than the smaller balloon.
Learn more on volume of sphere: brainly.com/question/9178703
Answer:
Explanation:
Because friction is always present, the actual mechanical advantage of a machine is always less than the ideal mechanical advantage.
