<span>Some solar eclipses are not total.</span>
Given that,
Mass of a frog, m = 0.5 kg
The frog leaps pushing off of the rock with an acceleration of 5.0 m/s².
To find,
The magnitude of the net force exerted on the frog as it leaps.
Solution,
Let the net force exerted on the frog is given by the formula as follows :
F = ma
Putting the values of m and a to find F as follows :
F = 0.5 kg × 5 m/s²
F = 2.5 N
So, the magnitude of net force is 2.5 N.
Answer:
Yes, extrapolated value do agree with accepted value of free-fall acceleration
Explanation:
Extrapolated value of acceleration up to 90 degree is accepted. There is an existing equation relating the acceleration of a body moving down a frictionless incline plane and the angle of inclination.
acceleration of the object is proportional to sine of the angle of inclination and the acceleration due to gravity. a=gsin(θ)
The value can be derived by calculating the acceleration at different angle of inclination and comparing the trend.