Answer:
Distance, d = 99990 meters
Explanation:
It is given that,
Speed of the train, v = 200 km/h = 55.55 m/s
Time taken, t = 1800 s
Let d is the distance covered by the train. We know that the speed of an object is given by total distance covered divided by total time taken. Mathematically, it is given by :
d = 99990 m
So, the distance covered by the train is 99990 meters. Hence, this is the required solution.
<h2>The work done , when body moves along the plane </h2>
Explanation:
A body is projected from bottom of the inclined plane . When body is going up the plane .
The downward force = m g sinθ is developed due to its weight
As body is moving upwards , the force of friction will act downwards
The force of friction = μ R
here μ is the coefficient of friction ans R is the normal reaction
Thus force of friction f = μ mg cosθ
Let the acceleration upwards is a
The upward force required = m a
Thus m a = mg sinθ + μ mg cosθ
or acceleration a = g ( sinθ + μ cosθ )
The work done in moving upwards W = F S
Thus W = mg ( sinθ + μ cosθ ) S
here S is the displacement on the plane
When body moves down , the force of friction acts upwards
Thus m a = m g ( sinθ - μ cosθ )
The work done W = m g ( sinθ - μ cosθ ) S
As the body is projected with velocity u
which can be calculated by the relation v² - u² = - 2 a X
Here v = 0 at the highest point
Thus u =
here a = g ( sinθ + μ cosθ )
Similarly , when it moves down , the initial velocity u = 0
Thus v² - 0 = 2 a x
or v =
here a = g ( sinθ - μ cosθ )