Question

What is the empirical formula for C3N12

Answer 1

Answer:

The emoirical formula for the given compound is :

$C_{1}N_{4}$ . It is simply written as CN4

Explanation:

Molecular formula : It  is the symbolic representation of chemical composition of different elements present in the molecule.

For example : Benzene is C6H6

It is the true composition of the elements.

Empirical Formula :It is the simple whole number ratio of the elements present in the given molecule.

For example :

The empirical formula of  Benzene is:

$C_{6}H_{6}= 6(CH)$

= CH

Steps to reach at the empirical formula :

• Search the common factor if any in the formula .

• divide the whole formula by the common factor.

In C3N12

3 is the common factor

divide each term by 3

C3 on dividing by 3 = C1

N12 on dividing by 3 = N4

Hence the empirical formula of the compound is CN4