Question

Light initially traveling in air n=1 is incident on a flat plane of glass n=1.6 at an angle of 20 degrees to the normal. find angle of the reflected and refracted light which enter the glass. (Draw picture)

Answer 1

Answer:

The reflected angle is 20 °.

The angle of refraction = 12.34°.

Explanation:

For reflection,  

Angle of incidence = Angle of the reflection.  

Thus,  

Given that the angle of incidence is 20 °

So, the reflected angle is 20°.

For refraction,  

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,  

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₁ is the refractive index of water which is 1

n₂ is the refractive index of water which is 1.6

So,  

$\frac {sin\theta_2}{sin20}=\frac {1}{1.6}$

${sin\theta_2}=0.2138$

Angle of refraction = sin⁻¹ 0.56 = 12.34°.