Answer:
= 0.7 A, = 1.3 A and ε = 7.4 V
Explanation:
From the given circuit, applying Kirchhoff's rule;
Ammeter reading, = 2 A
⇒ = + = 2 A
Dividing the circuit to loops 1 and 2.
a. From loop 1,
15 + 7 - 5 = 0
15 + 7 - 10 = 0 (since = 2 A)
7 - 5 = 0
= 0.7 A
But, = +
⇒ 2 = 0.7 +
= 1.3 A
b. From loop 2,
ε + 2 - 5 = 0
ε + 2 - 10 = 0
ε + 2.6 - 10 = 0
ε - 7.4 = 0
ε = 7.4 V
Therefore, = 0.7 A, = 1.3 A and ε = 7.4 V.
Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.The dimensions in which a wave propagates energy, The energy transfer
Answer:
hello your question is incomplete below is the complete question
A 2.0 kg block starts from rest on a positive x axis 3.0m from the origin and thereafter has an acceleration given by a= 4.0i - 3.0jin m/s2. At the end of 2.0 s, its angular momentum about the origin is ______.
answer : L = ( 2 kg ) [(-18m^2/s)k]
Explanation:
velocity vector(v) = (4.0i - 3.0j )(2.0s)
position vector(r) = ( 3.0m)i
determine the angular momentum about the origin
L = m ( r * v )
attached below is the detailed solution
Answer:
magnetic field strength is 0.315852 T
Explanation:
Given data
thick = 0.103 mm = 0.103 × 10^-3 m
charge-carrier density = 1.11 × 10^25 m^–3
hall voltage = 3.47 mV = 4.99 × 10^-3 V
current = 2.89 A
to find out
magnetic field strength
solution
we will apply here magnetic field strength formula i.e
magnetic field strength = hall voltage × charge-carrier density × magnitude of charge electron × thick / current
here put all these value and magnitude of charge electron is 1.6×10^-19 C
magnetic field strength = hall voltage × charge-carrier density × magnitude of charge electron × thick / current
magnetic field strength = 4.99 × 10^-3 × 1.11 × 10^25 × 1.6×10^-19 × 0.103 × 10^-3 / 2.89
magnetic field strength = 0.912811 / 2.89
magnetic field strength is 0.315852 T