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KonstantinChe [14]
3 years ago
11

The hydraulic tool holder is a type of what? A.port B. clamp C. Press D. Actuator​

Engineering
1 answer:
cestrela7 [59]3 years ago
6 0

answer: I think it is c. press because it presses on something

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A(n)<br> is a safety device commonly<br> used with a slotted nut.
liraira [26]

A safety device called a cotter pin. The cotter pin fits through a hole in the bolt or part. This keeps the nut from turning and possibly coming off.

5 0
3 years ago
When block C is in position xC = 0.8 m, its speed is 1.5 m/s to the right. Find the velocity of block A at this instant. Note th
Amanda [17]

Answer:

The answer is "2 m/s".

Explanation:

The triangle from of the right angle:

\to (x_c-0.8)+(1.5+y_4) +\sqrt{x_c^2 + 1.5^2}= constant

Differentiating the above equation:

\to V_c +V_A+ \frac{X_cV_c}{\sqrt{x_c^2 +1}}=0\\\\\to 1-V_A+ \frac{0.8 \times 1.5}{\sqrt{ 0.8^2+1.5}}=0\\\\

\to V_A=  \frac{1.2}{\sqrt{ 0.64+1.5}}+1\\\\

        = \frac{1.2}{ 1.46}+1\\\\= \frac{1.2+ 1.46}{ 1.46}\\\\ = \frac{2.66}{1.46}\\\\= 1.82 \ \frac{m}{s}\\\\= 2 \ \frac{m}{s}

3 0
3 years ago
The purification of hydrogen gas is possible by diffusion through a thin palladium sheet. Calculate the number of kilograms of h
diamong [38]

Answer:

M=0.0411 kg/h or 4.1*10^{-2} kg/h

Explanation:

We have to combine the following formula to find the mass yield:

M=JAt

M=-DAt(ΔC/Δx)

The diffusion coefficient : D=6.0*10^{-8} m/s^{2}

The area : A=0.25 m^{2}

Time : t=3600 s/h

ΔC: (0.64-3.0)kg/m^{3}

Δx: 3.1*10^{-3}m

Now substitute the  values

M=-DAt(ΔC/Δx)

M=-(6.0*10^{-8} m/s^{2})(0.25 m^{2})(3600 s/h)[(0.64-3.0kg/m^{3})(3.1*10^{-3}m)]

M=0.0411 kg/h or 4.1*10^{-2} kg/h

8 0
3 years ago
If you replace the text value in an associative dimension, the text value will not change when the
Nostrana [21]

Answer:

C

Explanation:

7 0
4 years ago
If the bending moment (M) is 4,176 ft-lb and the beam is an 1 beam, calculate the bending stress (psi) developed at a point with
SpyIntel [72]

Answer:

Bending stress at point 3.96 is \sigma_b = 1.37 psi

Explanation:

Given data:

Bending Moment M is 4.176 ft-lb = 50.12 in- lb

moment of inertia I = 144 inc^4

y = 3.96 in

\sigma_b = \frac{M}{I} \times y

putting all value to get bending stress

\sigma_b = \frac{50.112}{144} \times 3.96  

\sigma_b =  1.37 psi

Bending stress at point 3.96 is \sigma_b = 1.37 psi

3 0
4 years ago
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