Answer:
Mass of O = 8.2 gram
Explanation:
Given:
Mass of Fe = 10 g
Total volume = 18.2 g
Find:
Mass of O
Computation:
Using Conservation of total mass
Total volume = Mass of O + Mass of Fe
18.2 = Mass of O + 10
Mass of O = 8.2 gram
Answer:
a)
1-Pentanamine
2-Pentanamine
3-Pentanamine
3-methyl-2-butanamine
3-methyl-1-butanamine
2-methyl-1-butanamine
2-methyl-2-butanamine
2,2-dimethyl-1-propanamine
b)
2-pentanamine
3-methyl-2-butanamine
2-methyl-1-butanamine
Explanation:
Amines are organic compounds derived from ammonia by replacing the hydrogen atoms, one at a time with carbon-containing groups. The functional groups are R-NH₂, R₂-NH, and R₃-N
Amines are classified into primary, secondary, or tertiary according to the number of substituted hydrogen.
From the given question.
A compound with the molecular formula C₅H₁₃N was given;
The possible eight structural formula of the compound and those that exhibit chirality can be seen in the attached image below.
Answer:
Potassium
General Formulas and Concepts:
<u>Chem</u>
- Reading a Periodic Table
- Periodic Trends
- Ionization Energy - energy required to remove an electron from a given element
- Coulomb's Law
- Shielding Effect
- Z-effective and Forces of Attraction
Explanation:
The Periodic Trend for 1st Ionization Energy is increasing up and to the right. That means He would have the highest I.E and therefore take the most amount of energy to remove an electron.
Potassium and Gallium are both in Period 4. Potassium is element 19 and Gallium is element 31.
Potassium's electron configuration is [Ne] 4s¹ and Gallium's electron configurations is [Ne] 4s²3d¹⁰4p¹. Since both are in Period 4, they have the same number of core e⁻. Therefore, the shielding effect is the same.
However, since Gallium is element 31, it has 31 protons compared to Potassium, which is element 19 and has 19 protons. Gallium would have a greater Zeff than Potassium as it has more protons. Therefore, the FOA between the electrons and nucleus of Ga is much stronger than that of K. Thus, Ga requires <em>more</em> energy to overcome those FOA to remove the 4p¹ e⁻. Since K has less protons, it will have a smaller Zeff and thus less FOA between the e⁻ and nucleus, requiring <em>less</em> energy to remove the 4s¹ e⁻.
Answer:
(Fe(OH)2 + Na2SO4
Explanation:
Iron (II) hydroxide precipitate. Iron (II) hydroxide precipitate (Fe(OH)2) formed by adding few drops of a 1M solution of sodium hydroxide (NaOH) to 0.2 M solution ferrous sulfate (FeSO4). The reaction is FeSO4 + NaOH -> Fe(OH)2 + Na2SO4. This is an example of a double replacement reaction. Pure iron (II) hydroxide is white, however even trace amounts of oxygen make it greenish.
Percent error is [(abs(experimental - actual))/(actual)] * 100
(38.0 - 40.0 ) / 40.0 = 2.0 / 40 = 0.05
0.05 * 100 = 5
since there are 2 sigfigs, the answer is 5.0 %
I made the 2 positive since the absolute value of 38.0 - 40.0 was taken
There are only 2 sigfigs because of the subtraction of 38.0 - 40.0 gives 2.0, only 2 sigfigs
