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nikklg [1K]
3 years ago
9

Identify the molecule that effuses the fastest ch4 co ar or co2

Chemistry
2 answers:
Ksju [112]3 years ago
5 0
<span>CH4 will effuse the fastest. The speed of effusion is proportional to the speed of the gas molecules with faster molecules effusing fast than slower molecules. And the speed of the molecules at any given temperature is inversely related to the mass of the molecules with lighter molecules being faster. So let's take a look at the mass of the candidate molecules and see which is lighter and therefore faster. CH4 - Molar mass is about 16. CO - Molar mass is about 28 Ar - Molar mass is about 40 CO2 - Molar mass is about 44 If the 4 options, CH4 (methane) is by far the lightest, and therefore the fastest, so will effuse faster than the other 3 gasses.</span>
____ [38]3 years ago
5 0
I think CO2 because its something common LMFOA 
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Predict the precipitate that forms when aqueous solutions of silver nitrate an potassium chloride react to form products in a do
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Select the correct answer from each drop-down menu. In a voltaic cell, the electrons and is oxidized, while the electrons and is
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Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.

<h3 /><h3>What is a voltaic cell?</h3>
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Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.

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3 0
2 years ago
If a sample of oxygen gas originally at from 171.4 K has its temperature increased to 288.4 K and
julia-pushkina [17]

Answer:

V₂ = 0.95 L

Explanation:

Given data:

Initial temperature of gas = 171.4 K

Final temperature of gas = 288.4 K

Final volume = 1.6 L

Initial volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₂ = 1.6 L × 171.4 K / 288.4 k

V₂ = 274.24 L.K / 288.4 K

V₂ = 0.95 L

6 0
3 years ago
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