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4 years ago

HOW MANY KILOMETERS IS EARTH FROM THE SUN?

Physics

2 answers:

maria [59]4 years ago

7 0

Earth is 150 million kilometers away for the sun

dlinn [17]4 years ago

3 0

The Sun, the star of our Galaxy, the reason of our life, is at about 150 million kilometers from us: The Earth!
But in January, it gets a little more closer to 146 Million kilometers (that's the closest possible), and the furthest is 152 million kilometers in July.

Hope this Helps! :)

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What is the velocity of a plane that took 2 hours to travel 1000 miles north?

professor190 [17]

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3 years ago

What does the balloon of the air capacitor represent in an electrical capacitor?

bulgar [2K]

Answer:

The balloon prohibits the flow of air through the air capacitor.

Explanation:

Just like an electric capacitor has an insulator between the plates, the air capacitor has a balloon between the chambers.

6 0

3 years ago

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Which statement describes the horizontal acceleration of a projectile? It is –9.8 m/s2. It is 9.8 m/s2. It is constant. It is ze

lina2011 [118]

In a projectile, the horizontal acceleration is zero. The velocity remains constant at all times. However, the <u>vertical acceleration</u> is -9.81m/s^2.

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3 years ago

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How do we get this equation ??<br><br><br> H=V^2÷R

lesantik [10]

$H=\frac{V^2}{R}\times t$ is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = $H = I^2 Rt$ .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

$V\ \alpha\ I\\V=I\times R$ ...............................................(2)

From (2), Current (I) can be rewritten as

$I = \frac{V}{R}$ ........................................................(3)

Substituting (3) in (1), we get

$H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t$

3 0

3 years ago

Please hurry please

Ghella [55]

Answer:

0.765m

Explanation:

gravitational potential energy GPE = mass * acceleration due to gravity * height

Given

GPE = 30Joules

Mass m = 4kg

acceleration = 9.8m/s²

Required

Height h

From the formula

h = GPE/mg

h = 30/4(9.8)

h = 30/39.2

h = 0.765m\

Hence the height of the counter is 0.765m

4 0

3 years ago