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frozen [14]
4 years ago
14

HOW MANY KILOMETERS IS EARTH FROM THE SUN?

Physics
2 answers:
maria [59]4 years ago
7 0
Earth is 150 million kilometers away for the sun 

dlinn [17]4 years ago
3 0
The Sun, the star of our Galaxy, the reason of our life, is at about 150 million kilometers from us: The Earth!
But in January, it gets a little more closer to 146 Million kilometers (that's the closest possible), and the furthest is 152 million kilometers in July.

Hope this Helps! :)
You might be interested in
The Petronas twin towers in Malaysia and the Chicago Sears tower have heights of about 452 m and 443 m respectively. If objects
fredd [130]

Answer:

0.09 s

Explanation:

From the second equation of motion,

S=ut+\frac{1}{2}at^{2}

Here, u is the initial velocity, a is the acceleration due to gravity, t is time taken, and S is the total displacement or distance.

From the given problem,

initial velocity is zero for both the case.

And the distance of twin  tower of malaysia is, S_{1}=452m

And the distance of Sears tower of Chicago is, S_{1}=443m

Now,rearrange the distance equation for t.

t=\sqrt{\frac{2S}{a} }

So time difference.

\Delta t=\sqrt{\frac{2(452)}{9.8} }-\sqrt{\frac{2(443)}{9.8} }\\\Delta t=\sqrt{92.244898}-\sqrt{90.4081633}  \\\Delta t=9.60 s-9.51s\\\Delta t=0.09 s

Therefore, the difference in time, object will reach the ground is 0.09 s

8 0
3 years ago
How do distinctive rock strata support the theory of continental drift?
Scorpion4ik [409]

“It states that parts of the Earth's crust slowly drift atop a liquid core. The fossil record supports and gives credence to the theories of continental drift and plate tectonics. ... Continental Coastlines appearing to fit together,Fossil Distrubution, Distinctive Rock Strata, and Coal Distrubution.”

Hope this helps!

~Mia

4 0
4 years ago
PLEASE HELP ASAP!!!!!
Damm [24]

I believe the answer is resonance

6 0
3 years ago
Which of the following refers to the ability to do work
valina [46]
The ability to do work is called energy.
3 0
4 years ago
Read 2 more answers
At the presentation ceremony, a championship bowler is presented a 1.64-kg trophy which he holds at arm's length, a distance of
solong [7]

To solve the problem it is necessary to take into account the concepts of the kinetic equations for the description of the torque at the rate of force and distance.

By definition the torque is given by,

\tau = F*d

where,

F= Force

d = Distance

For the problem in question the mass of the trophy is 1.64Kg and the distance of the tropeo to the board (the shoulder) is 0.655m

PART A) For part A, the torque with the given mass and the stipulated torque in the horizontal plane must be calculated as well,

\tau = F*d

For Newton's second law

\tau = mg*d

\tau = 1.64*9.81*0.655

\tau = 10.5Nm

PART B) For part B there is an angle of 26 degrees with respect to the horizontal, therefore to know the net torque it is necessary to know the horizontal component to the formed angle, that is,

\tau = F*dcos\theta

\tau = mgdcos\theta

\tau = 1.64*9.81*0.655*cos26

\tau = 9.471Nm

3 0
3 years ago
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