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Elanso [62]
3 years ago
5

Can someone make a list of 10 simple things people can do to maintain fitness ? Please I literally need help.

Physics
2 answers:
ivanzaharov [21]3 years ago
6 0

Answer:

1. drink lots of water

2. eat healthy breakfast

3. plan your meals

4. set a deadline

5. exercise at least 30 minutes a day even 10 minutes 3 times a day is good

6. eat fruits and vegetables

7. eat whole grains instead of white

8. get a good night's sleep

9. stay motivated

10. take time for mental health

xz_007 [3.2K]3 years ago
6 0
1. CARDIO
2. HEALTHY DIET
3. STRETCHING
4. WORKING OUT
5. PHYSICAL ACTIVITIES
6. PAYING ATTENTION TO FOOD LABELS
7. STAYING AWAY FROM PROCESSED / SUGARY FOODS
8. EATING FRUIT
9. SPORTS
10. STAYING ACTIVE
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Which officeholders are elected by the electoral college
NikAS [45]

Answer:Electoral Vote

Explanation:i did it before

4 0
2 years ago
Describe the difference between distance, position, and displacement
nata0808 [166]

Answer:

Explanation:

<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>

<em>Displacement is the difference in the object's position from one time to another.</em>

<em>Distance is the total amount the object has traveled in a certain period of time.</em>

<em />

<em>I hope this helps!</em>

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5 0
2 years ago
What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
An engine absorbs 1749 J from a hot reservoir and expels 539 J to a cold reservoir in each cycle. a. What is the engine’s effici
Masja [62]

Answer:

a)η = 69.18 %

b)W= 1210 J

c)P=3967.21 W

Explanation:

Given that

Q₁ = 1749 J

Q₂ = 539  J

From first law of thermodynamics

Q₁   = Q₂ +W

W=Work out put

Q₂=Heat rejected to the cold reservoir

Q₁ =heat absorb by hot  reservoir

W= Q₁- Q₂

W= 1210 J

The efficiency given as

\eta=\dfrac{W}{Q_1}

\eta=\dfrac{1210}{1749}

\eta=0.6918

η = 69.18 %

We know that rate of work done is known as power

P=\dfrac{W}{t}

P=\dfrac{1210}{0.305}\ W

P=3967.21 W

8 0
3 years ago
A car speeds up from 18.54 m/s to<br> 29.52 m/s in 13.84 s.<br> The acceleration of the car is:
valkas [14]

Answer:

.7934m/s^{2}

Explanation:

Acceleration = change in velocity / change in time

A = 10.98m/s / 13.84s

A = .7934m/s^{2}

5 0
3 years ago
Read 2 more answers
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