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lesantik [10]
3 years ago
12

How many pounds of coal would you have to burn to generate enough heat to boil a 15 l kettle?

Chemistry
1 answer:
rjkz [21]3 years ago
7 0
Note that
The heating value of standard coal is about 30,080 kJ/kg
1 L of water has a mass of 1.0 kg

The mass of 15 L of water = 15 kg.
The latent heat of vaporization of water is about 2260 kJ/kg,
 The energy required to boil 15 L of water is
(2260 kJ/kg)*(15 kg) = 33900 kJ

The mass of coal required to provide this energy is
(33900 kJ)/(30080 kJ/kg) = 1.127 kg

Because 1 kg = 2.205 lb, the mass of coal required is
(1.127 kg)*(2.205 lb/kg) = 2.485 lb

Answer: 2.49 lb (nearest hundredth)

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Explanation:

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Which model failed to explain the
11Alexandr11 [23.1K]

Answer:

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Explanation:

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What is the mass in grams of 120 liters at STP oh He gas​
skad [1K]

The mass of He gas = 21.428 g

<h3>Further explanation</h3>

Given

120 liters of He gas​

Required

the mass in grams

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

Mol for 120 L :

\tt \dfrac{120}{22.4}=5.357~moles

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5 0
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