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Leviafan [203]
3 years ago
12

Can someone help with homework anyone? right now its science...

Chemistry
1 answer:
inna [77]3 years ago
8 0

Answer:

Organ

Explanation:

Cells work together to make tissues, tissues work together to make organs, organs works together to make the organ system, and the organ system works to help the organism stay alive and do all of the physical stuff._.

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Use the molar bond enthalpy data in the table to estimate the value of Δ∘rxn
MakcuM [25]

Answer:

ΔH°rxn = - 433.1 KJ/mol

Explanation:

  • CH4(g) + 4Cl2(g) → CCl4(g) + 4HCl(g)

⇒ ΔH°rxn = 4ΔH°HCl(g) + ΔH°CCl4(g) - 4ΔH°Cl2(g) - ΔH°CH4(g)

∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state

∴ ΔH°CCl4(g) = - 138.7 KJ/mol

∴ ΔH°HCl(g) = - 92.3 KJ/mol

∴ ΔH°CH4(g) = - 74.8 KJ/mol

⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)

⇒  ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol

⇒ ΔH°rxn = - 433.1 KJ/mol

4 0
3 years ago
Read 2 more answers
If the half-life of an element is 150 years, how much of a 400 gram sample would remain in 750 years?
photoshop1234 [79]

Answer:

y

Explanation:

5 0
2 years ago
What can break light apart
Hatshy [7]
Photons can sometimes break apart molecules
3 0
3 years ago
Determine the percent yield for the reaction between 98.7 g of
rjkz [21]
Convert 98.7 g Sb2S3 to mols.
Convert mols Sb2S3 to mols Sb4O6 using the coefficients in the balanced equation.
Convert mols Sb4O6 to grams Sb4O6. (This is the theoretical yield.)
Convert grams Sb4O6 to percent Sb4O6.
%Sb4O6 = [72.4/theoretical yield]*100


So basically your answer is 85.5%
7 0
3 years ago
Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct numbe
Lana71 [14]

Answer:

Explanation:

Given the equation:

\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}

The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.

The first step is to determine the algebraic value on the numerator.

Algebraic value = 9.8 - 231

= 7.49

The absolute uncertainty = \sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}

absolute uncertainty = \sqrt{(0.3)^3 + (0.01)^2}

= \sqrt{0.09 + 0.0001}

= 0.300167

∴

[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)

The division process now is:

\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}

Relative uncertainty = \dfrac{(\pm 0.300167)}{7.49}\times 100  \ , \  \dfrac{(\pm 0.6) }{8.5} \times 100

Relative uncertainty = ±4.007565% ,  ±7.058824%

\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}

\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}

\text{Relative uncertainty} = \sqrt{65.88757349}

\text{Relative uncertainty} = 8.117116

≅ 8%

The algebraic value = \dfrac{7.49}{8.5}

= 0.881176

≅ 0.88

The percentage of the relative uncertainty =\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100

By cross multiplying:

\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}

\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}

\text{Absolute uncertainty} (\%) = 0.0715260

\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}

Finally:

\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}

8 0
2 years ago
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