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allochka39001 [22]
3 years ago
14

Do you need to take into consideration the fact that the boat sinks lower into the water as water leaks in?

Physics
1 answer:
zzz [600]3 years ago
6 0
Yes because as more water leaks in the more water it will displace
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It takes a crane 59s to lift a flagstone using 342 W of power. How much work is done on the flagstone? ​
zepelin [54]

Answer: The work done on the flagstone is 20178 J

Explanation:

Power is the rate at which work is done . It is equal to the amount of work done divided by the time it takes to do the work.

Work=Power\times time

Given : work = ?

Power = 342 W = 342J/s

Time = 59 s

Work=342J/s\times 59s=20178J

Thus the work done on the flagstone is 20178 J

5 0
3 years ago
What does 'payback time' mean?
dimaraw [331]

Payback time is when someone has to take the consequences of what they have done in the past. You can use this expression to talk about good or bad consequences.

4 0
4 years ago
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A force of 9.00 newtons acts at an angle of 19.0° to the horizontal. What is its component in the horizontal direction?
g100num [7]
It would be helpful if you draw the figure of the problem. You will see that a right triangle would be constructed by the problem where 19.0 is the angle between the hypotenuse and the base of the triangle. It is said that the force acting is said to be 9.0 N  at the said angle to the horizontal. Using trigonometric relations,

cos 19 = adjacent / hypotenuse = horizontal component / 9
horizontal component = 8.51 N
5 0
3 years ago
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<img src="https://tex.z-dn.net/?f=See%20%5C%3A%20%20Attachment.%20%20%5C%3A%20" id="TexFormula1" title="See \: Attachment. \:
Tcecarenko [31]
So acceleration = (final velocity - initial velocity)/time

So (fv-iv)/t=a

(45-110)/4.5

Gives you (-130/9)km/h^2

You may have to convert the SI units so just follow my steps and change what must be changed
4 0
3 years ago
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A dolphin accelerates at -1.77 m/s2 for
Zepler [3.9K]

Answer:

-19.4 m

Explanation:

Given:

a = -1.77 m/s²

t = 3.33 s

v = -8.77 m/s

Find: Δx

Δx = vt − ½ at²

Δx = (-8.77 m/s) (3.33 s) − ½ (-1.77 m/s²) (3.33 s)²

Δx = -19.4 m

5 0
4 years ago
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