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allochka39001 [22]
3 years ago
14

Do you need to take into consideration the fact that the boat sinks lower into the water as water leaks in?

Physics
1 answer:
zzz [600]3 years ago
6 0
Yes because as more water leaks in the more water it will displace
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A man can jump 1.5 m on earth. calculate the approximate
Olegator [25]

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = \rho V

\rho = Density of planet

V = Volume of planet assuming it is a sphere = \dfrac{4}{3}\pi r^3

r = Radius of planet

Acceleration due to gravity on a planet is given by

g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}

So,

g\propto \rho r

Density of other planet = \rho_p=\dfrac{1}{4}\rho_e

Radius of other planet = r_p=\dfrac{1}{3}r_e

\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5

On the other planet

v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}

The man can jump a height of 18 m on the other planet.

5 0
3 years ago
So i want to start a dance academy. what do i do
timama [110]

Answer:

get students and a license

5 0
3 years ago
Read 2 more answers
the coefficient of static friction between a 40 kg picnic table and the ground below is .43. what is the greatest horizontal for
Gre4nikov [31]
The force equals the coefficient of static friction times the weight. Use gravity g=9.8 m/s^2
0.43*40*9.8=16.856 N
4 0
3 years ago
Read 2 more answers
A load of 54 N attached to a spring that ishanging vertically stretches the spring 0.15 m.What is the spring constant?Answer in
beks73 [17]

Answer:

300 N/m

Explanation:

given,

Load attached to the spring, W = 54 N

length of stretch of the spring, x = 0.15 m

spring constant= ?

Force applied on the spring is calculated by the equation

F = k x

where k is the spring constant

x is the displacement of the spring due to applied load

now,

54 = k × 0.15

k = \dfrac{54}{0.15}

k =300\ N/m

hence, the spring constant is equal to 300 N/m

8 0
3 years ago
Read 2 more answers
A cart is loaded with a brick and pulled at constant speed along an inclined plane to the height of a seat-top. If the mass of t
grandymaker [24]

Answer:

13.23J

Explanation:

PE = m*g*h

PE = (3 kg ) * (9.8 m/s/s) * (0.45 m)

3 0
3 years ago
Read 2 more answers
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