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galben [10]
3 years ago
8

What formed the rock of the canadian shield?

Physics
1 answer:
Svetllana [295]3 years ago
6 0
The Canadian Shield<span>, also called the Laurentian Plateau, or Bouclier canadien (French), is a large area of exposed Precambrian igneous and high-grade metamorphic </span>rocks<span> (geological </span>shield<span>) that forms the ancient geological core of the North American continent (the North American Craton or Laurentia).</span>
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White raven [17]
I think it's wavelength
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3 years ago
what is the purpose of a domain in science? do not copy any thing of the internet and they are not the right answer. I am learni
Leya [2.2K]

Answer:

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4 0
2 years ago
How to do this question?​
marissa [1.9K]

Answer:

i3 =11.014A

i5 = 3.15A

Explanation:

Here according to k'chofs first law

i1 =i2 + i3

i3 = i4 + i5

For determine the i1 you have to consider the resultant resistor of the system

4 , 1 and 3 resistors are in pararel

Then, Resultant is

1/4 + 1/1 + 1/3 = 1/ R

R = 12/19

For get total we have to add another remaining 3 resistor because of serious

Then Resultant is = 12/19 + 3

= 69/19

Then using V = IR

40 =i3* 69/19

i3 = 11.014 A

Other 3 resistors are parrarel because of this voltage of those resistors are same.

Then i inversely propotional to its resistor

Then ,

i5 * 2 = (i3-i5)*4/5

i 5 = 3.15 A

7 0
3 years ago
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zavuch27 [327]

Answer:

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Explanation:

Hope that helped lol!

8 0
2 years ago
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The deviation of a value (x) from the mean of the sample divided by the standard deviation (s)of the sample is known as the "z"
Ugo [173]

Answer:

true.

Explanation:

z-score gives an idea of how far the value of data is from the mean point. Basically is the measure of a standard deviation below or above the mean.

More the deviation of the data from the mean more is the standard deviation.

Z-score or value is calculated by the expression given below:

     z = \dfrac{x-\mu}{\sigma}

  x is the value

 μ is the mean

 σ is the standard deviation

Hence, the statement given is true.

6 0
3 years ago
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